Answer:
29. A.
1. its between B and C I think I'm not totally sure just guess on it try your best.
30. B.
No. The inequality is false.
In the given point (9,6) the second number is the Y value.
So if you replace Y with the given Y value of 6, the inequality is now 6 > 6 which is false since, 6 is = 6.
Answer:
Lets take the hypothesis
<em>zα/2 </em>
<em>- zα/2 </em>
Step-by-step explanation:
<em>α/2 = 0.10/2 = 0.05
</em>
<em>z(0.05) = 3.92
</em>
<em>-z(0.05) = -3.92
</em>
Answer:
B(6,-1)
Step-by-step explanation:
mid point of AB = (1,3)
MID POINT FORMULA=(x1+x2/2 , y1+y2/2)
1=x1+x2/2 , 3=y1+y2/2
2= -4 + x2 , 6 = 7 +y2
x2=6, y2=-1
Answer: See Below
<u>Step-by-step explanation:</u>
(b) Make a table of white ovals and black ovals. You will notice that
white starts with 3 and adds 3 to each design → 3 + 3(d - 1) = 3d
black starts with 4 and adds 4 to each design → 4 + 4(d - 1) = 4d
![\begin{array}{c|c|c}\underline{\text{Design \#}}&\underline{\text{white ovals}}&\underline{\text{black ovals}}\\1&3&4\\2&6&8\\3&9&12\\4&3(4)=12&4(4)=16\\5&3(5)=15&4(5)=20\\6&3(6)=18&4(6)=24\\\cdot&\cdot&\cdot\\\cdot&\cdot&\cdot\\\cdot&\cdot&\cdot\\n&3n&4n\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7Cc%7D%5Cunderline%7B%5Ctext%7BDesign%20%5C%23%7D%7D%26%5Cunderline%7B%5Ctext%7Bwhite%20ovals%7D%7D%26%5Cunderline%7B%5Ctext%7Bblack%20ovals%7D%7D%5C%5C1%263%264%5C%5C2%266%268%5C%5C3%269%2612%5C%5C4%263%284%29%3D12%264%284%29%3D16%5C%5C5%263%285%29%3D15%264%285%29%3D20%5C%5C6%263%286%29%3D18%264%286%29%3D24%5C%5C%5Ccdot%26%5Ccdot%26%5Ccdot%5C%5C%5Ccdot%26%5Ccdot%26%5Ccdot%5C%5C%5Ccdot%26%5Ccdot%26%5Ccdot%5C%5Cn%263n%264n%5Cend%7Barray%7D)
white ovals when design = 30 ---> 3d = 3(30) = 90
black ovals when design = 100 ---> 4d = 4(100) = 400
white ovals when design = 50 ---> 3d = 3(50) = 150
black ovals when design = 50 ---> 4d = 4(50) =<u> 200 </u>
TOTAL = 350
**********************************************************************************
(c) Make a table of rods and squares. You will notice that
rods start with 19 and add 12 to each design → 19 + 12(d - 1) = 12d - 7
squares start with 6 and add 4 to each design → 6 + 4(d - 1) = 4d + 2
![\begin{array}{c|c|c}\underline{\text{Design \#}}&\underline{\qquad \text{rods}\qquad }&\underline{\qquad \text{squares}\qquad }\\1&19&6\\2&31&10\\3&43&14\\4&12(4)-7=55&4(4)+2=18\\5&12(5)-7=67&4(5)+2=22\\6&12(6)-7=79&4(6)+2=26\\\cdot&\cdot&\cdot\\\cdot&\cdot&\cdot\\\cdot&\cdot&\cdot\\n&12n-7&4n+2\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7Cc%7D%5Cunderline%7B%5Ctext%7BDesign%20%5C%23%7D%7D%26%5Cunderline%7B%5Cqquad%20%5Ctext%7Brods%7D%5Cqquad%20%7D%26%5Cunderline%7B%5Cqquad%20%5Ctext%7Bsquares%7D%5Cqquad%20%7D%5C%5C1%2619%266%5C%5C2%2631%2610%5C%5C3%2643%2614%5C%5C4%2612%284%29-7%3D55%264%284%29%2B2%3D18%5C%5C5%2612%285%29-7%3D67%264%285%29%2B2%3D22%5C%5C6%2612%286%29-7%3D79%264%286%29%2B2%3D26%5C%5C%5Ccdot%26%5Ccdot%26%5Ccdot%5C%5C%5Ccdot%26%5Ccdot%26%5Ccdot%5C%5C%5Ccdot%26%5Ccdot%26%5Ccdot%5C%5Cn%2612n-7%264n%2B2%5Cend%7Barray%7D)
rods when design = 15 ---> 12d - 7 = 12(15) - 7 = 173
squares when design = 15 ---> 4d + 2 = 4(15) + 2 = 62