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timurjin [86]
3 years ago
8

What is the remainder when 399 is divided by 8?

Mathematics
2 answers:
gogolik [260]3 years ago
8 0

Answer:

When 399 is divided by 8 then it's remainder is 7.

algol [13]3 years ago
6 0

Answer:

7

Step-by-step explanation:

When dividing you can see that 8 goes in 399, 49 times so you multiply 49 by 8 you will get 392. Then you subtract 392 from 399

<h2>399-392=7</h2>

So the remainder is 7

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You are building a shed for growing plants and other vegetations. It has a sloped roof.
kherson [118]

Answer:

Its a i just took the test

Step-by-step explanation:

8 0
3 years ago
Estimate the product of 2.28 × 5.59 using compatible numbers.
Ierofanga [76]

The quotient of 2.28 × 5.59 using compatible numbers is approximately 12.75

<h3>What are products?</h3>

Quotients are result derived from the multiplication of two rational or integers. Given the expression

2.28 × 5.59

Convert to fraction

2.28 × 5.59 = 228/100  ÷  559/100
2.28 × 5.59= 127452/10000

2.28 × 5.59=  12.75

Hence the quotient of  2.28 × 5.59  using compatible numbers is approximately 12.75

Learn more on product here: brainly.com/question/673545

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3 0
2 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
4 years ago
The number of pizzas ordered on friday evenings between 5:30 and 6:30 at a pizza delivery location for the last 10 weeks is show
Ainat [17]
For a smoothing constant of 0.2

Time period – 1 2 3 4 5 6 7 8 9 10

Actual value – 46 55 39 42 63 54 55 61 52

Forecast – 58 55.6 55.48 52.18 50.15 52.72 52.97 53.38 54.90

Forecast error - -12 -.6 -16.48 – 10.12 12.85 1.28 2.03 7.62 -2.9
The mean square error is 84.12

The mean forecast for period 11 is 54.38
For a smoothing constant of 0.8

Time period – 1 2 3 4 5 6 7 8 9 10

Actual value – 46 55 39 42 63 54 55 61 52

Forecast – 58 48.40 53.68 41.94 41.99 58.80 54.96 54.99 59.80

Forecast error - -12 6.60 -14.68 0.06 21.01 -4.80 0.04 6.01 -7.80The mean square error is 107.17

The mean forecast for period 11 is 53.56


Based on the MSE, smoothing constant of .2 offers a better model since the mean forecast is much better compared to the 53.56 of the smoothing constant of 0.8.
7 0
3 years ago
Write an equation of a line in point-slope and slope intercept form that passes through the point (1, -8) and is perpendicular t
prisoha [69]

Answer:

11y-2x= -90

Step-by-step explanation:

for the point (1,-8)

x=1 and y= -8

for the equation,

2x -4y= -11

x= -1/m

m= -1/x

x = -1/ (-11/2 )

m= 2/11

so for the equation,

y-y1= m(x- x1)

y- -8=2/11(x-1)

11(y+8)= 2(x-1)

11y +88= 2x-2

11y-2x= -90

3 0
3 years ago
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