First, solve the area of the entire large rectangle (28)(45) = 1260
Next, find the area of the chunk that is cut out (11)(15) = 165
- we know the width is 15 because 45 - 6 - 24
Subtract the cut out piece from the overall rectangle 1260 - 165 = 1095
Area of a rectangle=length x width
You have two rectangles:
First rectangle (the biggest):
length=9 yd
width=12 yd-6 yd=6 yd
Area of the biggest rectangle=(9 yd)(6 yd)=54 yd²
Second rectangle (the smallest)
length=6 yd
width=3 yd
Area of the smallest rectangle=(6 yd)(3 yd)=18 yd²
Area of the ballroom=area of the biggest rectangle + area of the smallest rectangle.
area of the ballroom=54 yd² +18 yd²=72 yd²
I’m not sure if the 2 is counted in the equation or not
Since x=4, substitute it for x in the other equation
4+3y=29
3y=25
Y=8.333333333
2(4)+3y=29
8+3y=29
3y=37
y=12.33333333
