Ask question

Ask question

All categories

4 years ago

10

A submarine’s depth at 10:00 a.m. was ( -200ft). At noon, it descended an additional 500 feet. What was the submarine’s depth at

noon?

2 answers:

adelina 88 [10]4 years ago

4 0

The depth of the submarine was -700 ft at noon

tresset_1 [31]4 years ago

3 0

-700ft is the answer

You might be interested in

An engineer wants to know if the average amount of energy used in his factory per day has changed since last year. The factory u

m_a_m_a [10]

Answer:

<em> The calculated value Z = 1.8823 <1.96 at 0.05 level of significance</em>

<em> The average amount of energy used in his factory per day has changed since last year. </em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that mean of the Population = 2000 (MWH)

Given that size of the sample 'n' = 400

Given that mean of sample x⁻ = 2040 MWH

Given that the standard deviation = 425 MWH per day

<u><em>Step(ii):-</em></u>

<u><em>Null hypothesis:H₀: μ = 2000 (MWH)</em></u>

<u><em>Alternative Hypothesis:H₁: μ≠ 2000( MWH)</em></u>

<em>Test statistic</em>

<em> </em> $Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$ <em></em>

<em> </em> $Z = \frac{2040-2000}{\frac{425}{\sqrt{400} } }$ <em></em>

<em> Z = 1.8823</em>

<em>The calculated value Z = 1.8823 <1.96 at 0.05 level of significance</em>

<u><em>Final answer:</em></u><em>-</em>

<em> The calculated value Z = 1.8823 <1.96 at 0.05 level of significance</em>

<em> The average amount of energy used in his factory per day has changed since last year. </em>

3 0

3 years ago

the length of a rectangle is five times its width. if the perimeter of the rectangle is 96 ft, find its area.

romanna [79]

Answer:

lets say that the length is L and the width is W. With the given info, we can say that L=5W.

We know that the perimeter is all four sides added, so..

5W*4=20W

20W=96

W=4.8

L= 5*4.8=24

Area is equal to 24*4.8, which is 115.2

Voila! Your answer is 115.2 sq. ft!

5 0

3 years ago

a food company delivers its fruit in two types of boxes, large a small. A delivery of 7 large boxes and 9 small boxes has a tota

ivann1987 [24]

Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141

You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75

A large box weighs 18.75 kg; a small box weighs 15.75 kg.

5 0

3 years ago

Ava has two frogs. This is 1/3 the number of frogs that Heather has. How many frogs does Heather have?

lesya692 [45]

Answer:

2x3=6 and that the number of frogs heather has or you can do this Ava has 2 frogs and heather has 1/3 more then take the 2 and add it to the 1 and that makes three. then take both of the threes and add them together and you then have the same number of 6

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

45/84 is it in simplest form

balandron [24]

The simplest form is 15/28
Correct me if I'm wrong. Hope this helps!

3 0

3 years ago