D
there is always a 1 infront of a variable but since x2 has the largest degree it gives it priority over the others so what ever numbe in front of it is the leading coefficient
27,700 is .336 how many are all 100%
27,700 / .336 = X/ 1
82,440 employees
1.50c + 2.50a = 1100
c + a = 500
multiply the second equation by -1.50
1.50c + 2.50a = 1100
-1.50c - 1.50a = -7.50
9514 1404 393
Answer:
(i) x° = 70°, y° = 20°
(ii) ∠BAC ≈ 50.2°
(iii) 120
(iv) 300
Step-by-step explanation:
(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.
x = 70
The angle marked y° is the supplement to the one marked 160°.
y = 20
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(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...
tan(∠BAC) = BC/BA = 120/100 = 1.2
∠BAC = arctan(1.2) ≈ 50.2°
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(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.
bearing of C = 70° +50.2° = 120.2°
The three-digit bearing of C from A is 120.
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(iv) The bearing of A from C is 180 added to the bearing of C from A:
120 +180 = 300
The three-digit bearing of A from C is 300.
For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8