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vlabodo [156]
3 years ago
6

Question 10 (10 points)

Mathematics
1 answer:
Verdich [7]3 years ago
4 0

Answer: $-84

Step-by-step explanation:

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A 2-column table with 10 rows. Column 1 is labeled Classes with entries Hall, Benny, Leggo, Talle, Flower, Gomez, Range, Book, T
Alex787 [66]

Answer:

range: 20

median: 38

Lower quartile and upper quartile: 29 and 42.5

Interquartile range: 13.5

Which value was affected the most: range

8 0
3 years ago
How can you determine which quadrant an equation falls in?
Sunny_sXe [5.5K]
\bf 2sec^2(\theta )-tan(\theta )-3=0
\\\\\\
2[1+tan^2(\theta )]-tan(\theta )-3=0\implies 2+2tan^2(\theta )-tan(\theta )-3=0
\\\\\\
2tan^2(\theta )-tan(\theta )-1=0\implies [2tan(\theta )+1][tan(\theta )-1]=0\\\\
-------------------------------\\\\

\bf 2tan(\theta )+1=0\implies 2tan(\theta )=-1\implies tan(\theta )=-\cfrac{1}{2}
\\\\\\
\measuredangle \theta \approx
\begin{cases}
5.82\ radians\\
2.68\ radians
\end{cases}\qquad 
\begin{array}{llll}
\textit{the tangent is negative}\\
\textit{tha means the II and IV quadrants}
\end{array}\\\\
-------------------------------\\\\

\bf tan(\theta )-1=0\implies tan(\theta )=1\implies \measuredangle \theta =
\begin{cases}
\frac{\pi }{4}\\
\frac{7\pi }{4}
\end{cases}
\\\\\\
\textit{the tangent is positive}\\
\textit{that means the I and III quadrants}


bear in mind that tangent is sine/cosine or y/x

for the tangent to be negative, the signs of "y" and "x" must differ, and that happens only on the II and IV quadrants

and for the tangent to be positive, the signs must be same, and that's only on I and III quadrants.
8 0
3 years ago
Which distance measures 7 units?
goldfiish [28.3K]

where's the graph??

I can't answer this without the graph

3 0
4 years ago
Read 2 more answers
Can someone help me plz :)
rewona [7]

Answer:

C. 10

Step-by-step explanation:

Supplementary means that they form a 90° angle.

5 0
4 years ago
Read 2 more answers
A team of seven workers started a job, which can be done in 11 days. On the morning of the fourth day, several people left the t
Harman [31]

Hello!

To first solve this problem, let's look at how much the workers would've finished when they were still a group.

Since the job could've been originally done in 11 days with 7 people, and they only worked for 3 days (with 7 people), they originally finished 3/11 of the job.

Now, let's look at how much each person finishes of the job in one day.

Since 7 workers can finish the job in 11 days, this means that 1 worker can finish the job in 77 days, translating to that one worker does 1/77 of the job in one day.

Let's connect these ideas. There is 8/11 of the project remaining, and this was finished in 14 days. This means, every day, 4/77 of the project was finished. (8/11 divided by 14)

Since we know one worker does 1/77 of the job per day, and every day, 4/77 of the job was finished, 4 workers were on the team.

Therefore, 7-4, 3 workers left the team.

Hope this helped!

3 0
4 years ago
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