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3 years ago

6

A secret recipe requires you mix chocolate and cream cheese in the ratio 3:2, based on weight. If you use 21 oz of chocolate, ho

w much cream cheese do you need?

1 answer:

Alexus [3.1K]3 years ago

3 0

Answer: 14 oz

Step-by-step explanation:

CH/CR 3:2

3x/3=21/3

x=7

2*7=14 oz.

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The amount of money Chaz earned for walking dogs is given in the table. Can the relationship be described by a constant rate? Ex

mojhsa [17]

Answer:

Yes, the relationship can be described by a constant rate of $18.75 per dog

Step-by-step explanation:

see the attached figure to better understand the problem

Let

x ----> the number of dogs

y ---> the amount of money earned

we have the points

$(6,112,50), (8,150), (11,206.25)$

step 1

Find the slope with the first and second point

$(6,112,50), (8,150)$

$m=(150-112.50)/(8-6)=18.75$

step 2

Find the slope with the first and third point

$(6,112,50), (11,206.25)$

$m=(206.25-112.50)/(11-6)=18.75$

Compare the slopes

The slopes are the same

That means, that the three points lies on the same line

therefore

Yes, the relationship can be described by a constant rate of $18.75 per dog

7 0

3 years ago

What is the denotation of the word "stealing” in this excerpt?

MrMuchimi

Answer:

being deceptive

committing a crime

keeping a secret

taking over

5 0

3 years ago

X²+y²-6x+14y-1=0<br> and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0

3 years ago

May I please receive help?

Artyom0805 [142]

4, -1/4 -1,

we can do this simply by

(y2-y1)/(x2-x1)

and simplifying

6 0

2 years ago

Does the table represent a proportional relationship? Show your work!

wel

Yes, adding going up one every time, 5,6,7,8

4 0

3 years ago