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AURORKA [14]
3 years ago
8

Please help me with the screenshot.

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
3 0

Refer to the attachment for the answer

Answer is inside the orange boxes with green ticks on them

Refer to the attachment for the answer

Answer is inside the orange boxes with green ticks on them

x = 0.7 when y = 0.6

            OR

x = 0.6 when y = 0.7

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Each music class sings 8 songs a week. How. Many songs does each class sing in 5 weeks 6 weeks 7 weeks
crimeas [40]

Answer:

40, 48, 56

Step-by-step explanation:

8x5 is 40

8x6 is 48

8x7 is 56

I hope this helps have a good day

7 0
3 years ago
24 inches per minute converts to how many miles per day
12345 [234]

Answer:

0.545455

Step-by-step explanation:

3 0
3 years ago
Find the angle between the given vectors to the nearest tenth of a degree. u = , v = (2 points)
Liono4ka [1.6K]

Answer:

<h2>3.6°</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Find the angle between the given vectors to the nearest tenth of a degree.

u = <8, 7>, v = <9, 7>

we will be using the formula below to calculate the angle between the two vectors;

u*v = |u||v| cos \theta

\theta is the angle between the two vectors.

u = 8i + 7j and v = 9i+7j

u*v = (8i + 7j )*(9i + 7j )

u*v = 8(9) + 7(7)

u*v = 72+49

u*v = 121

|u| = √8²+7²

|u| = √64+49

|u| = √113

|v| = √9²+7²

|v| = √81+49

|v| = √130

Substituting the values into the formula;

121= √113*√130 cos θ

cos θ = 121/121.20

cos θ = 0.998

θ = cos⁻¹0.998

θ = 3.6° (to nearest tenth)

Hence, the angle between the given vectors is 3.6°

5 0
4 years ago
Truck brakes can fail if they get too hot. In some mountainous areas, ramps of loose gravel are constructed to stop runaway truc
pickupchik [31]

Kinetic engery = -1/2mv^2

Work = Fd

Combine:

-1/2mv^2 - Fd = 0

-1/2mv^2 = (0.30*15000*9.81*cos(6))d = 0

Multiply both sides by 2:

v^2 = 2d(0.30*9.81*cos(6))

Solve for d:

d=v^2 / 2(0.30*9.81*cos96))

v = speed:

d = 35^2 / 2*0.30 * 9.81 * cos(6)

d = 1225 / 5.85376

d = 209.27 meters. Round answer as needed.

7 0
4 years ago
The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to
Firdavs [7]

Rewrite the boundary lines <em>y</em> = -1 - <em>x</em> and <em>y</em> = <em>x</em> - 1 as functions of <em>y </em>:

<em>y</em> = -1 - <em>x</em>  ==>  <em>x</em> = -1 - <em>y</em>

<em>y</em> = <em>x</em> - 1  ==>  <em>x</em> = 1 + <em>y</em>

So if we let <em>x</em> range between these two lines, we need to let <em>y</em> vary between the point where these lines intersect, and the line <em>y</em> = 1.

This means the area is given by the integral,

\displaystyle\iint_T\mathrm dA=\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy

The integral with respect to <em>x</em> is trivial:

\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy

For the remaining integral, integrate term-by-term to get

\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line <em>y</em> = 1 and (0, -1)), so its area is 1/2*4*2 = 4.

6 0
3 years ago
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