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Sati [7]
3 years ago
8

What is the range of the function f(x) = 1/2 square root of x ? Anyone

Mathematics
1 answer:
siniylev [52]3 years ago
6 0

Answer:

The range is f(x) ≥ 0

Step-by-step explanation:

The range of the function is defined as the set of values of the dependent variable for which the function is defined.

Here the function f(x) = 1/2 √x is defined for all values of x which are greater than or equal to zero or we can say all non-negative real numbers.

So, the range is  f(x) ≥ 0

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write each of the following products in standard polynomial form. (a) (x+3)(x-2)(x-8) (b) (x+2)(x-2)(x+3)(x-3)
Annette [7]

Answer: A)x²+x-6   B) 2x²-13

Step-by-step explanation: A) (x+3)(x-2)(x-8) = x²-2x+3x-6 = x²+x-6

B) (x+2)(x-2)(x+3)(x-3) =→ x²-2x+2x-4 = x²-4

→x²-3x+3x-9 = x²-9

∴x²-4+x²-9 = <u><em>2x²-13</em></u>

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3 years ago
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3 years ago
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Solve the equation using the Zero­Product Property. 6x(3x + 1) = 0
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4 0
3 years ago
What is 3% of $30.00?
CaHeK987 [17]
% means out of 100 so 1%=1/100

so 3%=3/100
$30.00=3000 cents
so you multiply 3/100 by 3000 =(3*3000)/100
you can cross out two zeros at the bottom and on the top and get
(3*30)/1 or 90/1 or 90 cents
3 0
3 years ago
Read 2 more answers
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