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Lemur [1.5K]
3 years ago
13

This program uses hours, pay rate, state tax and fed tax to determine gross

Computers and Technology
1 answer:
Kryger [21]3 years ago
8 0

Answer:

See explaination

Explanation:

#include <fstream>

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

// Fill in the code to define payfile as an input file

ifstream payfile;

float gross;

float net;

float hours;

float payRate;

float stateTax;

float fedTax;

cout << fixed << setprecision(2) << showpoint;

// Fill in the code to open payfile and attach it to the physical file

// named payroll.dat

payfile.open("payroll.dat");

// Fill in code to write a conditional statement to check if payfile

// does not exist.

if(!payfile)

{

cout << "Error opening file. \n";

cout << "It may not exist where indicated" << endl;

return 1;

}

ofstream outfile("pay.out");

cout << "Payrate Hours Gross Pay Net Pay"

<< endl << endl;

outfile << "Payrate Hours Gross Pay Net Pay"

<< endl << endl;

// Fill in code to prime the read for the payfile file.

payfile >> hours;

// Fill in code to write a loop condition to run while payfile has more

// data to process.

while(!payfile.eof())

{

payfile >> payRate >> stateTax >> fedTax;

gross = payRate * hours;

net = gross - (gross * stateTax) - (gross * fedTax);

cout << payRate << setw(15) << hours << setw(12) << gross

<< setw(12) << net << endl;

outfile << payRate << setw(15) << hours << setw(12) << gross

<< setw(12) << net << endl;

payfile >> hours ;// Fill in the code to finish this with the appropriate

// variable to be input

}

payfile.close();

outfile.close();

return 0;

}

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(a) Store last 7 digits of your student ID in a vector (7 element row or column vector). Write a MATLAB code which creates a 7x7
astra-53 [7]

Answer:

MATLAB code explained below with appropriate comments for better understanding

Explanation:

clc

clear all

ID = [1 2 3 4 5 6 7]; % Replace this with your student ID

%(a)

A = zeros(7);

for i=1:7

 

A(i,i)= ID(i);

 

end

fprintf('A =\n');

disp(A);

B = diag(ID);

fprintf('B =\n');

disp(B);

fprintf('Both A and B are same\n');

%(b)

if(mod(A(6,6),2)==0)

fprintf('A(6,6) is even\n');

else

fprintf('A(6,6) is odd\n');

end

%(c)

if(A(3,3)>0)

fprintf('A(3,3) is positive\n');

else if(A(3,3)<0)

fprintf('A(3,3) is negative\n');

else

fprintf('A(3,3)=0\n');

end

end

%(d)

fprintf('\nRequired series : ');

n = 35;

while n>=0

fprintf('%i',n);

if(n>0)

fprintf(', ');

end

n = n - 5;

end

fprintf('\n');

%(e)

n = input('\nInput an integer : ');

fprintf('%i! = ',n);

F = 1;

while n>1

F = F * n;

n = n - 1;

end

fprintf('%i\n',F);

%(f)

clear all

x = [3 7 2 1];

y = [4 3 9 1];

A = 0;

C = x(1);

for i=1:length(x)

A = A + x(i)*y(i);

B(i) = x(i)/y(i);

if(min(x(i),y(i))<C)

C = min(x(i),y(i));

end

end

C = 1/C;

fprintf('\nA = %i\n',A);

fprintf('B = ');

disp(B)

fprintf('C = %0.5g\n',C);

%(g)

clear all

A = randi([5 25],[1,10]);

maxA = A(1);

for i = 2:10

if(maxA<A(i))

maxA = A(i);

end

end

minA = A(1);

i = 2;

while i<11

if(minA>A(i))

minA = A(i);

end

i = i+1;

end

fprintf('\nA = ');

disp(A);

fprintf('maxA = %i\n',maxA);

fprintf('minA = %i\n',minA);

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%output

A =

1 0 0 0 0 0 0

0 2 0 0 0 0 0

0 0 3 0 0 0 0

0 0 0 4 0 0 0

0 0 0 0 5 0 0

0 0 0 0 0 6 0

0 0 0 0 0 0 7

B =

1 0 0 0 0 0 0

0 2 0 0 0 0 0

0 0 3 0 0 0 0

0 0 0 4 0 0 0

0 0 0 0 5 0 0

0 0 0 0 0 6 0

0 0 0 0 0 0 7

Both A and B are same

A(6,6) is even

A(3,3) is positive

Required series : 35, 30, 25, 20, 15, 10, 5, 0

Input an integer : 6

6! = 720

A = 52

B = 0.7500 2.3333 0.2222 1.0000

C = 1

A = 25 14 7 10 13 17 10 17 19 9

maxA = 25

minA = 7

>>

5 0
3 years ago
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