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vazorg [7]
3 years ago
15

(a) find the slope m of the tangent to the curve y = 5/ x at the point where x = a > 0.(b) find equations of the tangent line

s at the points (1, 5) and 4, 5 2 .
Mathematics
1 answer:
Trava [24]3 years ago
4 0
<span>(a) the slope of curve is calculated from the derivative of the curve expression y=5/x. In this problem, the slope m=-5/(a^2). (b) x=1, y=5,and m=-5, the tangent line is y-5=-5*(x-1). x=4, y=5/4, and m=-5/16, the tangent line is y-5/4=-5/16*(x-4)</span>
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3 years ago
lets say you have two line segments , ab and cd which bisects each other at point E. explain why ac = ab
Bond [772]

Answer:

When a line segment is bisected into 2 halves, the two halves are equal. In this case, when AB is bisected by CD, AE and BE would be equal and each point on CD should be equidistant from point A and point B. Therefore, AC = AB.

4 0
2 years ago
If EF=9x+14, FG=56, and EG=250, find the value of x.
nexus9112 [7]

Answer:

Value of x =20

Step-by-step explanation:

Given: EF = 9x+14 units , FG = 56 units and EG = 250 units.

Segment Addition Postulates states the following for 3 points that are collinear.

i.e, Let three points A, B and C are collinear and B is between A and C.

i,e AC = AB + BC

By Segment addition postulates; solve for x;

EG = EF + FG

Substitute the given values we get;

250 = 9x + 14 + 56

or

250 = 9x + 70

Subtract 70 on both sides we get;

250 -70 = 9x + 70 -70

Simplify:

180 = 9x

Divide both sides by 9 we get;

\frac{180}{9} = \frac{9x}{9}

Simplify:

x = 20

Therefore, the value of x =20


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