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gogolik [260]
3 years ago
13

Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589.

Mathematics
1 answer:
olga_2 [115]3 years ago
4 0

Given:<span>

<span>segment AU = 20x + 108, 
UB = 273, 
BC = 703,
UV = 444, 
AV = 372 and 
AC = 589. 

</span>Point U lies on AB and V lies on AC.</span>

UV is perpendicular to AC.

 

Therefore, the similar triangles are AUV and ABC

<span>

So the similarity is: segment AU / segment UV = segment AB / segment BC</span>

 

<span>20x + 108       20X + 381
---------       = ---------------
372                      589</span>

<span>

(20x + 108)* 589 = (20X + 381)*372</span>

<span>

11780 X + 63612 = 7440X + 141732


4340 X - 78120 = 0


4340 X = 78120</span>

<span>

X = 78120/4340 = 18
</span><span>

Answer: x = 18</span>

 

To check:

 

<span>AU = 20*18 + 108 = 360 + 108 = 468

AB = 741

468/372 = 741/589 </span>

<span>Which the two are equal ratios</span>

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