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3 years ago

4. What are the points of discontinuity? Are they all removable? Please show your work.

1 answer:

7 0

If you are given the equation y = (x-5) / (x-5)(x-1), you have to cancel x-5 in the equation and get y = 1 / (x-1). The points of discontinuity are 5 and 1. It can be obtained by equating the factors to zero.

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Answer:

The answer is

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Step-by-step explanation:

Remember that Taylor says that

$f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }$

For this case

$f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18$

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Step-by-step explanation:

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