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Anon25 [30]
3 years ago
14

Please help I will mark smartest!

Mathematics
1 answer:
zvonat [6]3 years ago
4 0

Answer:

2cm

Step-by-step explanation:

you dives both the number in the bigger one by 3 to g 2cm

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Determine where the real zeros of f(x)=x^4-2x^3+x-2 are located.
siniylev [52]

Answer:

a. at -1 & 2

Step-by-step explanation:

The given function is

f(x)=x^4-2x^3+x-2.

Equate the function to zero.

x^4-2x^3+x-2=0.

Factor by grouping;

x^3(x-2)+1(x-2)=0

Factor further;

(x-2)(x^3+1)=0

Apply the zero product property;

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Solve for x;

x=2,x^3=-1

\Rightarrow x=2,x=\sqrt[3]{-1}

\therefore x=2,x=-1

4 0
3 years ago
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Answer:

36

Step-by-step explanation:

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3 years ago
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Zina [86]
In my opinion B would be the best answer
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Which is a zero of the quadratic function f(x) = 9x2 - 54x – 19?<br> x= 1/3 <br> x=3 1/3
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Step-by-step explanation:

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3 years ago
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Answer:

for the "which fraction is larger" I believe it would be 7/9

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