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4 years ago

Write the equation 4X -3Y = 12 in the form Y =MX +b

Mathematics

1 answer:

USPshnik [31]4 years ago

4 0

Answer:

Step-by-step explanation:

we have 4x-3y=12

-3y=-4x+12

-y=-4x+12/3

we have 12=3*4 so we remove 3 that is up and 3 that is down

-y=-4x+4

then we get y=+4x+4

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The combined height of one fir tree and one pine tree is 212121 meters. The height of 444 fir trees stacked on top of each other

inn [45]

Answer: The height of each fir tree is 9 meters, and the height of each pine tree is 12 meters.

Step-by-step explanation:

Let x= height of each fir tree, y = height of each pine tree.

As per given, we have

x+y = 21 (i)

4x=y+24 (ii)

From (ii),

$4x-y=24$ (iii)

Add (i) and (iii), we get

$5x=45\\\\\Rightarrow\ x=\dfrac{45}{5}\\\\\Rightarrow\ x=9$

Put value of x in (i), we get

$9+y=21\Rightarrow y=12$

Hence, the height of each fir tree is 9 meters, and the height of each pine tree is 12 meters.

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3 years ago

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Bradon played basketball he made 3/5 of the points the 1st game the team made 60 points and 40 points in the second game how man

Leno4ka [110]

Answer:

I dont know sorry

Step-by-step explanation:

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3 years ago

Brian ate 1/5 of a pie. The colin ate 1/5 of the pie, and david ate 1/5 of the pie.

sleet_krkn [62]

Answer:

2/5

Step-by-step explanation:

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3 years ago

What is the perimeter of a square with a side length of 15 inches?

nexus9112 [7]

60 in^2 will be your answer.

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3 years ago

Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g

SpyIntel [72]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see $\bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad B
\end{array}$

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.

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3 years ago

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