Answer:
(b) The interquartile range of B is greater than the interquartile range of A.
(d) The median of A is the same as the median of B.
Explanation:
Given


So:

Required
Select all true statements
(a) & (d) Median Comparisons


Arrange the data:




--- average of 5th and 6th

Option (d) is correct because both have a median of: 2
(b) & (c) Interquartile Range Comparisons


First, calculate the lower quartile (Q1)
[Odd n]
[Even n]


This means that:


Next, calculate the upper quartile (Q3)
[Odd n]
[Even n]

This means that:

The interquartile range is 
So, we have:


(b) is true because B has a greater IQR than A
(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.
The upper quartile and the interquartile range of A and B are not equal
Answer:
1. As the cell size increases, the ratio of surface area to volume DECREASES
2. It depends on the unit of the ratio 6:1. If it is in cm−1, then it means that it is similar to a cell of size 1 cm^3, which is normally too big to get materials from the surface
.
3. A Small cell has a large surface area/volume ratio and therefore can exchange molecules with it's external environment rapidly. So, Here cell with ratio 6:1 is smaller and have ability to better transportation across it's membrane as compared to other cell with ratio 3:1
HOPE THIS HELPS!!!