All categories

3 years ago

Line p has a slope of -3/4.Line q is parallel to line p.What is the slope of line q?

1 answer:

4 0

The slope would also be -3/4 since they are parallel they would have the same slope but different y-intercepts and no solution.

You might be interested in

Pls pls help asap pls

Anon25 [30]

Answer:

The answer is option 2

Step-by-step explanation:

Working out above

5 0

2 years ago

Read 2 more answers

Simplify by combining like terms -17+2(6x-1)+5

earnstyle [38]

$\huge\boxed{12x-14}$

Start with the original expression.

$-17+2(6x-1)+5$

Use the Distributive Property — multiply $2$ by both $6x$ and $-1$ .

$-17+12x-2+5$

Combine the like terms — add up all the constants.

$-14+12x$

Reorder the terms.

$\large\boxed{12x-14}$

5 0

3 years ago

Read 2 more answers

1. is the expression <img src="https://tex.z-dn.net/?f=8x8%5E5" id="TexFormula1" title="8x8^5" alt="8x8^5" align="absmiddle" cla

Lady_Fox [76]

Answer:

Step-by-step explanation:

No, because 8x8^58x85 only takes the 8 that it is up against to the fifth power, but (8x8)^5(8x8)5 takes the whole expression to the fifth power.

4 0

2 years ago

Read 2 more answers

What is the area of a sector with a central angle of 8 π/11 radians and a radius of 7.2 ft? use 3.14 for π and round your final

coldgirl [10]

Answer:

$59.19 ft^2$

Step-by-step explanation:

step 1

Find the area of the circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=7.2\ ft$

$\pi =3.14$

substitute

$A=(3.14)(7.2)^{2}$

$A=162.78\ ft^2$

step 2

we know that

The area of a circle subtends a central angle of 2π radians

using proportion

Find out the area of a sector with a central angle of 8 π/11 radians

$\frac{162.78}{2\pi }\frac{ft^2}{rad} =\frac{x}{(8\pi/11)}\frac{ft^2}{rad} \\\\x=162.78(8/11)/2\\\\x=59.19\ ft^2$

7 0

3 years ago

Solve for x.

xz_007 [3.2K]

Answer:

$\displaystyle -2,66 ≈ x\:or\:0,66 ≈ x$

Step-by-step explanation:

All work is shown above.

I am joyous to assist you anytime.

6 0

3 years ago