Wait I’m confused about 5.100 is that money ?
Step-by-step explanation:
Since, f(x) is a cosine function, it is periodic.
<u>Maximum : ( - 1 + </u><u>10<em>k</em></u><em><u> </u></em><u>, 28)</u> ; where <em>k</em> belongs to <em>Z</em>
Minimum : (4 + 10<em>k</em> , 22)
<u>Cycle No. 1</u> : k = 1
(A) The first occurrence of highest temperature in the cycle is on <u>day 9</u> after June 1 i.e. ( <u>June 10</u>) with <u>28 °C</u>.
<u>Cycle No. 1</u> : k = 0
(B) The first occurrence of lowest temperature in the cycle is on <u>day 4</u> ( <u>June 15</u>) with <u>22 °C</u>.
Part A.
We could take, for example:
For x ≥ -3 we have vertical line (x-intercept = -3) and shaded region on the right side of the line.
For y ≥ 3 we have horizontal line (y-intercept = 3) and shaded region above that line.
Part B.
Simply, substitute x and y coordinates of D and E <span>to the system of inequalities from part A, and check if its is true, what we get.
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so point D is a solution,
and point E is also a solution to <span>our system of inequalities.
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Part C.
There are two ways we could do that. First is the same as in part B. We substitute x and y coordinates of each school and check if inequality is true or false:
So Timothy can attend schools C and F.
We can also draw a graph of that inequality (pic 2).
One solution
n/3=15 is 45 so one solution