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Dimas [21]
3 years ago
5

How do u do positive and negatives

Mathematics
2 answers:
aleksley [76]3 years ago
7 0
Negative and a positive =positive
Negative and a negative=positive
Positive and a positive =positive
(Doesn’t apply with addition)
Oduvanchick [21]3 years ago
5 0

well if its 2 negatives multiplied it will change to a positve and if its a negative times a postive it will change to a negative

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Gail and 3 of her friends all share half of a pie. All the pieces in the pie put together make up 180 degrees. Gail and her frie
Pachacha [2.7K]
No the angle of each piece should be 60 degrees, if the three pieces were to be 25 each that would only add to 75
8 0
3 years ago
Given h(x) = 2x - 3 , solve for when h(x) = - 3 .
FrozenT [24]

Answer:

h(x)=-3;x=0

Step-by-step explanation:

When given h(x), you are in effect, being given the output of the function.

So, placing h(x)=-3 in place for h(x)

We get

-3=2x-3

Where -3+3=2x

0=2x

x=0

So, x=0

8 0
3 years ago
Which of these is an example of a literal equation?
Ahat [919]

Answer: B. 12=9+3x

Step-by-step explanation:

A. It is an equation, but you can’t really do anything with it, let alone solve it.

C. 30+6 does not equal to 62, so definitely not.

D. 3x-4y is something, but there is no equa sign.

So, your andswer is B. 12=9+3x

8 0
3 years ago
Read 2 more answers
If sin theta equals 12 divided by 13 and theta is in quadrant 2 cos20 equals? and cos theta equals?
Anni [7]

Answers:

  • cos(2theta) = -119/169
  • cos(theta) = -5/13

=====================================================

The given info is:

  • sin(theta) = 12/13
  • theta is in quadrant II

From that, we can use the pythagorean trig identity to find that cos(theta) = -5/13. Keep in mind that cosine is negative in quadrant II.

Now use the trig identity below to compute cos(2theta)

\cos(2\theta) = \cos^2(\theta)-\sin^2(\theta)\\\\\cos(2\theta) = \left(\frac{-5}{13}\right)^2-\left(\frac{12}{13}\right)^2\\\\\cos(2\theta) = \frac{25}{169}-\frac{144}{169}\\\\\cos(2\theta) = \frac{25-144}{169}\\\\\cos(2\theta) = -\frac{119}{169}\\\\

Other options you could use are these identities

\cos(2\theta) = 2\cos^2(\theta)-1\\\\

or

\cos(2\theta) = 1-2\sin^2(\theta)\\\\

3 0
3 years ago
I need an answer to this, I dont get it, wouldnt it be impossible due to like terms? g3b=5x+2
Serjik [45]

Answer:

Step-by-step explanation:

hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii bot

x^{2} x^{2} \geq x^{2} \neq \geq \geq

4 0
3 years ago
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