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3 years ago

How do u do positive and negatives

2 answers:

7 0

Negative and a positive =positive
Negative and a negative=positive
Positive and a positive =positive
(Doesn’t apply with addition)

Oduvanchick [21]3 years ago

5 0

well if its 2 negatives multiplied it will change to a positve and if its a negative times a postive it will change to a negative

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Nadya [2.5K]

8 is the answererrr :))))))

3 0

3 years ago

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suppose two different fractions with the same denominators are both less than 1 Can their sum equal 1? can their sum be greater

pochemuha

The sum could be greater than 1 but not equal to 1.

6 0

4 years ago

Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z

Oliga [24]

Given the expression

$54m^3n\:+\:81m^4n^2$

Apply exponent rule: $a^{b+c}=a^ba^c$

$54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn$ ∵ $m^4n^2=m^3mnn$

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

$=2\cdot \:27m^3n+3\cdot \:27m^3mnn$

Factor out the common term: 27m³n

$=27m^3n\left(2+3mn\right)$

Therefore,

$54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)$

Given the expression

$15x^2y^3z+25x^3y^2z+35x^2y^2z$

Apply exponent rule: $a^{b+c}=a^ba^c$

$15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z$

Rewrite as

$=3\cdot \:5y^2x^2zy+5\cdot \:5y^2x^2zx+7\cdot \:5y^2x^2z$

Factor out common term 5y²x²z

$=5y^2x^2z\left(3y+5x+7\right)$

Therefore,

$15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)$

8 0

3 years ago

Write the equation of a circle with center (7.0) with radius 3.

harina [27]

Answer:

2.3

Step-by-step explanation:

so the 7.0 gets dived by the 3 because the radius is half of the circle.

5 0

3 years ago

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Graph the following lines and write the equation in slope-intercept form. With y intercept of −3 and an x intercept of −4.5.

makvit [3.9K]

Answer:

$y=-\frac{2}{3}x-3$

Step-by-step explanation:

To write the equation of a line we need 2 points. We know:

If the y-intercept of the line is -3 then the point is (0,-3).

If the x-intercept of the line is -4.5 then the point is (-4.5,0).

Using these two point, we will find the slope and then substitute it into the point slope form $y-y_1=m(x-x_1)$ with a point.

Slope: $m=\frac{0--3}{-4.5-0}=\frac{0+3}{-4.5}=\frac{3}{-4.5}=-0.6667$

This decimal is -2/3. We will now substitute -2/3 and (0,-3) into the point slope form.

$y--3=-\frac{2}{3}(x-0)\\y+3=-\frac{2}{3}(x)\\y+3=-\frac{2}{3}x\\y=-\frac{2}{3}x-3$

6 0

3 years ago