Answer:
½ sec²(x) + ln(|cos(x)|) + C
Step-by-step explanation:
∫ tan³(x) dx
∫ tan²(x) tan(x) dx
∫ (sec²(x) − 1) tan(x) dx
∫ (sec²(x) tan(x) − tan(x)) dx
∫ sec²(x) tan(x) dx − ∫ tan(x) dx
For the first integral, if u = sec(x), then du = sec(x) tan(x) dx.
∫ u du = ½ u² + C
Substituting back:
½ sec²(x) + C
For the second integral, tan(x) = sin(x) / cos(x). If u = cos(x), then du = -sin(x) dx.
∫ -du / u = -ln(u) + C
Substituting back:
-ln(|cos(x)|) + C
Therefore, the total integral is:
½ sec²(x) + ln(|cos(x)|) + C
Answer:
37
Step-by-step explanation:
first you need to add 1 plus 4 which is 5. then square it so it becomes 25. Then using order of operations do 6 times 2 which is 12 and add it to 25 to get 37.
Answer:
<em>1,172.5cm²</em>
Step-by-step explanation:
Total surface area of a box = 2(LW + WH + LH)
L is the length = 11.5cm
W is the width = 7cm
H is the height = 1.5cm
Substitute
TSA = 2(11.5(7) + 7(1.5) + (11.5)(1.5))
TSA = 2(80.5+10.5+17.25)
TSA = 2(117.25)
TSA = 234.5cm²
<em>Hence the total surface area of a stack of five such compact disc boxes will be 5(234.5) = 1,172.5cm²</em>
The answer you want is going to be A)
, because all you have to do is add the exponents which -4+-10 would be -14 so therefore the answer you want is going to be A)
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