Answer:
Step-by-step explanation:
Arranging the data in ascending order we have :
24 , 30 , 32 , 32 , 34 , 35 , 37 , 39 , 50
(i) The minimum value is therefore 24
(ii) To find the lower quartile , we will need to find the median , that is the number in the middle , the number in the middle is 34 , therefore , the median is 34. Since we are dealing with odd data , that is the total number of data given is 9 , which is an odd number , we will not include the median in the lower quartile , therefore , the lower half of the data are :
24 , 30 , 32 , 32
To find the lower quartile , we will find the median of the lower half.
Median of the lower half = 
= 31
Therefore , Lower quartile = 31
(iii) Median = 34
(iv) To find the upper quartile , we will write out the upper half , which are :
35 , 37 , 39 , 50
We will then find the median of the upper half , which will be 37 + 39 / 2
= 76/2
=38
Therefore , Upper quartile = 38
(iv) To find the maximum , we will identify the highest number , therefore , the maximum = 50
(v) Interquartile range = upper quartile - lower quartile
Interquartile range = 38 - 31
Interquartile range = 7
(B) outlier is a data point that differs significantly from other observations
minimum = 24
maximum = 50
median = 34
lower quartile = 31
upper quartile = 38
interquartile range = 7
To find the outliner , we will follow the following steps
(i) multiply the interquartile range by 1.5 = 7 x 1.5 = 10.5
(ii) add it the upper quartile = 10.5 + 38 = 48 .5
(ii) subtract it from the lower quartile = 31 - 10 . 5 = 20 .5
This means that the boundary of the outliner are 20.5 and 48 . 5
The only number that falls outside this is 50
Therefore , there is an outliner
