The subtraction of complex numbers 
is cos(π)+i sin(π).
Given 
[cos(3π/4+i sin(3π/4) and 
=cos (π/2) +i sin(π/2)
We have to find the value of .
A complex number is a number that includes real number as well as a imaginary unit in which 
. It looks like a+ bi.
We have to first solve 
and then we will be able to find the difference.
[ cos (3π/4)+i sin (3π/4)]
[cos(π-π/4)+ i sin (π-π/4)]
= [-cos(π/4)+sin (π/4)]
=(-1/+1/)
=
=0
cos(π/2)+i sin (π/2)
=0+i*1
=1
Now putting the values of 
,
=-1
=-1+i*0
=cos (π)+i sin(π)
Hence the value of difference between is cos(π)+i sin(π).
Learn more about complex numbers at brainly.com/question/10662770
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I believe the answer is a = b+c^2/c(x-b)
Sorry if incorrect but hope this helps!
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Answer:
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Step-by-step explanation:
Answer:
Pythagorean Theorem:
a^2 + b^2 = c^2
6^2 + b^2 = 12^2
36 + b^2 = 144
b^2 = 108
b = 10.4
Let me know if this helps!
Answer:
Fish Population The population of a certain species of fish has a relative growth rate of 1.2 %per year. It is estimated that the population in 2000 was 12 million. (a) Find an exponential model for the population tyears after 2000 . (b) Estimate the fish population in the year 2005 (c) Sketch a graph of the fish population.
Step-by-step explanation:
