The answer is 2285.92 in³.
STEP 1: Calculate the volume of the log: V1 = ?
STEP 2: Calculate the volume of the cylinder: V2 = ?
STEP 3: Subtract these two volumes to get <span> the volume of the remaining portion of the log: V = V1 - V2
The volume of a cylinder is:
V = </span>π · r² · h
(π = 3.14, r - radius, h - height)
It is given:
h1 = h2 = h = 28 in (height of the log is the same as the height of the cylinder)
r1 = 7.5 in
r2 = 5.5 in
STEP 1: Calculate the volume of the log: V1 = ?
V1 = π · r1² · h = 3.14 · 7.5² · 28 = 4945.5 in³
STEP 2: Calculate the volume of the cylinder: V2 = ?
V2 = π · r2² · h = 3.14 · 5.5² · 28 = 2659.58 in³
STEP 3: Subtract these two volumes to get the volume of the remaining portion of the log:
V = V1 - V2 = 4945.5 in³ - 2659.58 in³ = 2285.92 in³
Y=-6x+8 is a linear equation because the x is not an exponent. It also is a straight line, not a curve (parabola) or exponential growth rate. I hope I helped! ^u^
Answer:
When using this technique, the AOQ:
improves (AOQ becomes a smaller fraction).
Step-by-step explanation:
AOQ simply means Average Outgoing Quality, which improves with inspection. It is a part of an organization's Acceptance Sampling Plan, usually designed to meet product quality and risk level targets. The plan draws samples from a population of items. Then it tests the samples. It only accepts the entire population if the sample is considered good enough. It also rejects the population when the sample is poor enough. In the plan, information about sample size and critical acceptance or rejection numbers are clearly indicated. Acceptance sampling is common in most business environments because it has been found to be more economical than doing 100% inspection of incoming production input and output.
Answer:
x = 4
Step-by-step explanation:
A vertical line at x = 4 ( all coordinates with x coordiante = 4)