Answer:
Statement C is the only one that is necessarily true for exons 2 and 3. It is also true for exons 7 and 8. While statements A and B could be true, they don’thave to be. Because the protein sequence is the same in segments of the mRNA that correspond to exons 1 and 10, neither choice of alternative exons (2 versus 3, or 7 versus 8) can alter the reading frame. To maintain the normal reading frame—whatever that is—the alternative exons must have a number of nucleotides that when divided by 3 (the number of nucleotides in a codon) give the same remainder. Since the sequence of the a-tropomyosin gene is known, it is possible to check to see the actual state of affairs. Exons 2 and 3 both contain the same number of nucleotides, 126, which is divisible by 3 with no remainder.
Answer:
I think option (C) is right answer
First move the x from the right side to the left by subtracting. 3x-6+2x-x=-2. combine like terms. 4x-6=-2. add six to both sides. 4x=4. divide 4 on both sides. x=1. hope this helped!
Answer:
TAGTC
Explanation:
There are four different nucleotides in DNA: adenine, thymine, cytosine and guanine.
The bases pair like so:
A with T (adenine with thymine)
C with G (cytosine with guanine)
The DNA sequence given is :
ATCAG
Match As with Ts, Ts with As, Cs with Gs and Gs with Cs.
The sequence of nucleotides that would bond with the sequence above is:
TAGTC
A monomer can be defined as the molecule that is capable of binding in long chains. The monomers bind together to form different polymers by the process of polymerization.
The monomer of carbohydrate is monosacchride. The monomer of proteins is amino acid, and that of lipids is glycerol and fatty acids. These three macromolecules are wrongly paired in the question.
The monomer of nucleic acids is nucleotide. This is correctly matched.
Hence, the correct answer is 'Option B - nucleic acids - nucleotides'.