Answer:
(10/3, -1)
Step-by-step explanation:
So there are two different ways.
First you could address for y and fitting it into the number cruncher. one condition for y1 and another for y2. At that point go second follow and press 5 and afterward press enter multiple times to discover the convergence.
the subsequent path is to tackle by hand. I would recommend address the primary condition for y and attachment the condition tackled for y into the other condition. so y = - 3x + 9 and 3x-5y=15. At that point you could do 3x - 5(- 3x+9) = 15. At long last address for x and plug in x into the two conditions to check whether you get a similar y esteem.
The appropriate response ought to be (10/3, - 1)
Answer:
step 2
Step-by-step explanation:
not really sure how to explain hope this helps
Since we know AD, CD and angle D, we can use the law of cosines, which states that
![AC^2 = AD^2+CD^2 - 2AD\cdot CD\cos(D)](https://tex.z-dn.net/?f=AC%5E2%20%3D%20AD%5E2%2BCD%5E2%20-%202AD%5Ccdot%20CD%5Ccos%28D%29)
Plugging the values, we have
![AC^2 = 17^2+13^2 - 2\cdot 17\cdot 13\cos(42)](https://tex.z-dn.net/?f=AC%5E2%20%3D%2017%5E2%2B13%5E2%20-%202%5Ccdot%2017%5Ccdot%2013%5Ccos%2842%29)
Which leads to
![AC^2 = 458 - 442\cos(42) \approx 129.530](https://tex.z-dn.net/?f=AC%5E2%20%3D%20458%20-%20442%5Ccos%2842%29%20%5Capprox%20129.530)
Taking the square root, we have
![AC \approx \sqrt{129.530} \approx 11.3811](https://tex.z-dn.net/?f=AC%20%5Capprox%20%5Csqrt%7B129.530%7D%20%5Capprox%2011.3811)