9-3÷1/3+1= PLEASE HELP!!

Mathematics

2 answers:

frosja888 [35]3 years ago

6 0

1.5

9-(3÷1)/3+1= 9-3/3+1

= 6/3+1=6/4

=1.5

step by step explanation: first you need to apply the rules of BODMAS and divide the 3 by the 1 then you are left with 9-3 which is 6 then evaluate what 3+1 is which is 4, now to get your final answer you divide the 6 by the 4 = 6/4 = 1.5.

enyata [817]3 years ago

5 0

Answer:

Step-by-step explanation:

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The vertices of ΔMNO are M (1, 3), N (4, 9), and O (7, 3). The vertices of ΔPQR are P (3, 0), Q (4, 2), and R (5, 0). Which conc

vodka [1.7K]

Answer:

They are similar by the definition of similarity in terms of a dilation.

Step-by-step explanation:

Given:

The vertices of ΔMNO are M (1, 3), N (4, 9), and O (7, 3). The vertices of ΔPQR are P (3, 0), Q (4, 2), and R (5, 0).

To choose: the correct option

Solution:

According to distance formula distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

For ΔMNO,

$MN=\sqrt{(4-1)^2+(9-3)^2}=\sqrt{(3)^2+(6)^2}=\sqrt{45}\\NO=\sqrt{(7-4)^2+(3-9)^2}=\sqrt{(3)^2+(-6)^2}=\sqrt{45}\\\\MO=\sqrt{(7-1)^2+(3-3)^2}=\sqrt{(6)^2+(0)^2}=\sqrt{36}=6\\$

For ΔPQR,

$PQ=\sqrt{(4-3)^2+(2-0)^2}=\sqrt{(1)^2+(2)^2}=\sqrt{5}\\QR=\sqrt{(5-4)^2+(0-2)^2}=\sqrt{(1)^2+(-2)^2}=\sqrt{5}\\\\PR=\sqrt{(5-3)^2+(0-0)^2}=\sqrt{(2)^2+(0)^2}=2\\$