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3 years ago

How many 1/4 hours are in a 1 hour

Mathematics

2 answers:

Rufina [12.5K]3 years ago

8 0

15 1/4 hours are in 1 hour

inn [45]3 years ago

6 0

4 because 1/4 +1/4 +1/4 1/4 =4 it's simple math

You might be interested in

The perimeter of a triangular lot is 72 meters one side is 16 meters and the other side is twice the first side find the length

marta [7]

16= 32 =48. 72- 48 = 24. The third side of the triangle is 24! Hope this helps, have a great day! :)

8 0

3 years ago

A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the

Orlov [11]

Answer:

95.44% probability that the sample proportion will differ from the population proportion by less than 0.03.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question:

$p = 0.05, n = 212, \mu = 0.05, s = \sqrt{\frac{0.05*0.95}{212}} = 0.015$

What is the probability that the sample proportion will differ from the population proportion by less than 0.03?

This is the pvalue of Z when X = 0.03 + 0.05 = 0.08 subtracted by the pvalue of Z when X = 0.05 - 0.03 = 0.02. So

X = 0.08

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.08 - 0.05}{0.015}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772

X = 0.02

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.02 - 0.05}{0.015}$

$Z = -2$

$Z = -2$ has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

95.44% probability that the sample proportion will differ from the population proportion by less than 0.03.

6 0

3 years ago

Smartness competition prove your smart! wanna join I tell you problems

dalvyx [7]

What are the problems?

7 0

4 years ago

What is the 6th term of the geometric sequence where a1 = 1,024 and a4 = −16? 1 −0.25 −1 0.25

VLD [36.1K]

The n-th term is given by

$a_n=a_1\cdot r^{(n-1)}\qquad\text{where r is the common ratio}$

Then we can find the common ratio from the given terms.

$\dfrac{a_4}{a_1}=\dfrac{a_1\cdot r^{(4-1)}}{a_1}=r^3=\dfrac{-16}{1024}=\left(\dfrac{-1}{4}\right)^3\\\\r=\dfrac{-1}{4}\\\\a_6=1024\left(\dfrac{-1}{4}\right)^5=-1$

The appropriate choice is -1.

8 0

3 years ago

Read 2 more answers

In the year 2006, a person bought a new car for $24000. For each consecutive year after that, the value of the car depreciated b

sweet [91]

Answer:

$15,746.400

Step-by-step explanation:

The computation of the car value in the year 2010 is shown below:

Since the new car brought in the year of 2006 at $24,000

And, it would be depreciation by 10%

So, in the year 2010 the car value would be

= $24,000 × (1 - 0.10)^4

= $24,000 × 0.9^4

= $15,746.400

5 0

3 years ago