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lozanna [386]
3 years ago
14

There is a recipe for barbecue sauce where the mixture is composed of four ingredients.in any quantity,the following is the make

up of the mixture.if three quarts of the barbecue sauce are to be made,how many cups of brown sugar are needed
Mathematics
1 answer:
anzhelika [568]3 years ago
5 0
You will need four cups of brown sugar

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Suppose it is known that the distribution of purchase amounts by customers entering a popular retail store is approximately norm
iragen [17]

Answer:

a. 0.691

b. 0.382

c. 0.933

d. $88.490

e. $58.168

f. 5th percentile: $42.103

95th percentile: $107.897

Step-by-step explanation:

We have, for the purchase amounts by customers, a normal distribution with mean $75 and standard deviation of $20.

a. This can be calculated using the z-score:

z=\dfrac{X-\mu}{\sigma}=\dfrac{85-75}{20}=\dfrac{10}{20}=0.5\\\\\\P(X

The probability that a randomly selected customer spends less than $85 at this store is 0.691.

b. We have to calculate the z-scores for both values:

z_1=\dfrac{X_1-\mu}{\sigma}=\dfrac{65-75}{20}=\dfrac{-10}{20}=-0.5\\\\\\z_2=\dfrac{X_2-\mu}{\sigma}=\dfrac{85-75}{20}=\dfrac{10}{20}=0.5\\\\\\\\P(65

The probability that a randomly selected customer spends between $65 and $85 at this store is 0.382.

c. We recalculate the z-score for X=45.

z=\dfrac{X-\mu}{\sigma}=\dfrac{45-75}{20}=\dfrac{-30}{20}=-1.5\\\\\\P(X>45)=P(z>-1.5)=0.933

The probability that a randomly selected customer spends more than $45 at this store is 0.933.

d. In this case, first we have to calculate the z-score that satisfies P(z<z*)=0.75, and then calculate the X* that corresponds to that z-score z*.

Looking in a standard normal distribution table, we have that:

P(z

Then, we can calculate X as:

X^*=\mu+z^*\cdot\sigma=75+0.67449\cdot 20=75+13.4898=88.490

75% of the customers will not spend more than $88.49.

e. In this case, first we have to calculate the z-score that satisfies P(z>z*)=0.8, and then calculate the X* that corresponds to that z-score z*.

Looking in a standard normal distribution table, we have that:

P(z>-0.84162)=0.80

Then, we can calculate X as:

X^*=\mu+z^*\cdot\sigma=75+(-0.84162)\cdot 20=75-16.8324=58.168

80% of the customers will spend more than $58.17.

f. We have to calculate the two points that are equidistant from the mean such that 90% of all customer purchases are between these values.

In terms of the z-score, we can express this as:

P(|z|

The value for z* is ±1.64485.

We can now calculate the values for X as:

X_1=\mu+z_1\cdot\sigma=75+(-1.64485)\cdot 20=75-32.897=42.103\\\\\\X_2=\mu+z_2\cdot\sigma=75+1.64485\cdot 20=75+32.897=107.897

5th percentile: $42.103

95th percentile: $107.897

5 0
3 years ago
Can i have some help?? Please???????????????
Sergeeva-Olga [200]
the second is a negative slope due to the fact the line is going the the left and the ind variable is breakfast dep is performance
4 0
3 years ago
HELP ME!!! solve for x
liq [111]

Answer:

x = 13.5 units

Step-by-step explanation:

Segment drawn to join the two sides of the triangle is parallel to third side of the triangle.

Therefore, by basic proportionality theorem:

\frac{12}{27}  =  \frac{6}{x}  \\  \\ x =  \frac{27 \times 6}{12}  \\  \\  \huge \red{ \boxed{x = 13.5 \: units}}

3 0
3 years ago
What is 7/10 - 1/10 in its simplest form
Elenna [48]
3/5 cause you get the lowest common denominator
4 0
2 years ago
Read 2 more answers
How to solve z+2/z-3=5/-3
OLEGan [10]
(z+2)= (z-3)(5/-3)
z+2 = 5z/-3 +5
-3= 2z/-3
9= 2z
9/2 = z
5 0
3 years ago
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