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3 years ago

When the positive integer n is divided by 7, the remainder is 2. What is the remainder when 5n is divided by 7?

Mathematics

1 answer:

ser-zykov [4K]3 years ago

6 0

Therefore the reminder is 3 when 5n is divided by 7.

Step-by-step explanation:

we know that

Dividend = quotient × Divisor +Reminder

⇔ n = Q(n) × 7 + 2 [ let Q(n) is quotient]

multiplying by 5 both sides

5n = 5 Q(n) ×7 + 2×5

⇔5n = 5 Q(n) ×7 +10

⇔5n= 5 Q(n) ×7 +7 +3

⇔ 5n = (5Q(n) +1) × 7 +3

Therefore the reminder is 3 when 5n is divided by 7.

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If Landon checks his pulse for 12 minutes, what is his rate if he counts 1560 beats?

Lynna [10]

It is 130 beats per minute.

Step-by-step explanation:

Just divide 1560 by 12.

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3 years ago

Read 2 more answers

The prisms and two nets shown below:<br><br> Plzzz answer part A B and C for BRILLIANT ANSWER

Arlecino [84]

Part A: Net A is correct
Net B is incorrect because de triangular sides do not close the opening left in both sides.

Part B: AB=3 in., BC=5in., CD=8.6in.

Part C: The surface area of the prism is the area of the the big rectangle in the net + the area of the 2 triangles

Area of the big rectangle
8.6• ( 3+4+5)= 103.2 in ^2
Area of the triangles
If we get the 2 trangles together along their longest side we get another rectangle
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3 years ago

Choose the correct option.Immersive Reader (1 Point) (A) z-5=2 is an equation and z=5 is the solution of this equation (B) t+2&g

melomori [17]

Answer:

<h3>Find the explanation below</h3>

Step-by-step explanation:

A) Given the equation z - 5 = 2

To get the solution, we will add 5 to both sides and find z as shown;

z - 5 = 2

z - 5 + 5 = 2 + 5

z + 0 = 2+5

z = 7

Hence z = 5 is not the solution of the equation but z = 7

B) Given the inequality expression t+2>5

Substract 2 from both sides of the equation;

t+2 - 2>5 - 2

t + 0> 3

t>3

Hence the solution t = 4 is not true for the expression. The solution is t > 3

C) Given the expression x-2=2, to get the solution to the expression, you will add 2 to both sides of the equation;

x - 2+ 2 = 2 + 2

x + 0 = 4

x = 4

Therefore x = 4 is the solution of this equation.

Based on the question, only Option C is correct

8 0

2 years ago

1-sin60÷cos60=1-Tan30÷1+Tan30

ipn [44]

Step-by-step explanation:

LHS=(1-sin60)/cos60

=(1-√3÷2)/1÷2

=2(1-√3÷2)

=2-√3

RHS=(1-tan30)/(1+tan30)

={1-(1÷√3)}/{1+(1÷√3)}

={(√3-1)/√3}/{(√3+1)/√3}

=(√3-1)/(√3+1)

={(√3-1)(√3-1)}/{(√3+1)(√3-1)}

=(3-√3-√3+1)/(3-1)

=(4-2√3)/2

=2-√3

Therefore LHS=RHS

8 0

3 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago