Answer:
3.) ![\displaystyle y - 4 = 4[x - 1]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20-%204%20%3D%204%5Bx%20-%201%5D)
2.) ![\displaystyle y + 5 = 2[x + 2]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20%2B%205%20%3D%202%5Bx%20%2B%202%5D)
1.) ![\displaystyle y + 3 = 1\frac{1}{5}[x + 5]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20%2B%203%20%3D%201%5Cfrac%7B1%7D%7B5%7D%5Bx%20%2B%205%5D)
Step-by-step explanation:
In the Point-Slope Formula, ![\displaystyle y - y_1 = m[x - x_1],](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20-%20y_1%20%3D%20m%5Bx%20-%20x_1%5D%2C)
all the negative symbols give the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.
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368 miles / 16 gallons
368/16=23 miles per gallon
Answer:
198.4
Step-by-step explanation:
multiply the mass value by 16
Answer:
b(b/a)^2
Step-by-step explanation:
Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then
b = a - (p% × a) = a(1-p%)
b/a = 1 - p%
p% = 1 - b/a = (a-b)/a
Let the worth of the car on December 31, 2012 be c
then
c = b - (b × p%) = b(1-p%)
Let the worth of the car on December 31, 2013 be d
then
d = c - (c × p%)
d = c(1-p%)
d = b(1-p%)(1-p%)
d = b(1-p%)^2
d = b(1- (a-b)/a)^2
d = b((a-a+b)/a)^2
d = b(b/a)^2 = b^3/a^2
The car's worth on December 31, 2013 = b(b/a)^2 = b^3/a^2
