Let the price of the 3rd card be c. Now we can write the equation:
c + (c + 20) + (c + c + 20) = 160 .........(1)
Simplifying the left hand side of equation (1), we get:
4c + 40 = 160 .........(2)
Subtracting 40 from both sides of equation (2) gives:
4c = 120
from which c = $30.
Therefore the price of the second card = 30 + 20 = $50
and the price of the first card = 30 + 50 = $80.
Answer:
x = 1
y = 1.7
z = 60⁰
work:
z = 60 because the three angles add to 180⁰ and 180⁰ - 90⁰ - 30⁰ = 60⁰
in a 30-60-90 triangle, the hypotenuse is twice the length of the shorter leg, so x = 1.
the longer leg is the short leg * Sq rt of 3
Sq rt of 3 to the nearest tenth is 1.7, so 1.7 * 1 is still 1.7, so y = 1.7.
Step-by-step explanation:
In a standard deck of 52 cards, there are 2 red aces, 2 red Queens, and 13 spades. That leaves 35 cards for everything else.
For the game to be fair, the cost must equal the expected value. The expected value is the sum of each outcome times its probability.
C = (12) (13/52) + (20) (2/52) + (38) (2/52) + (0) (35/52)
C = 68/13
C ≈ 5.2308
Answer:We're looking for a,b such that
\dfrac{9x-20}{(x+6)^2}=\dfrac a{x+6}+\dfrac b{(x+6)^2}
Step-by-step explanation:
