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Olin [163]
3 years ago
5

Could these triangles be congruent?

Mathematics
2 answers:
Mama L [17]3 years ago
8 0

Answer:

yes, if AB ≅ DE

Step-by-step explanation:

Triangles are said to be congruent if they have the same sides and the same angles.

The following measures are used to determine if triangles are congruent:

1) Angle-side-angle: If two angles and a side of a triangle is equal to two angles and corresponding side of another triangle, then they are congruent.

2) Side-side-side: If all three sides of a triangle is equal to three sides of another triangle, then the two triangles are congruent.

3) Side angle side: If two sides and an included angle of a triangle is equal to the two sides and corresponding angle of another triangle, then they are congruent.

4) Hypotenuse - leg: If the hypotenuse and one leg of a triangle is equal to the hypotenuse and leg of another triangle then they are congruent.

From the triangles  DEF and ABC, already, they already have one equal triangle that is ∠F = ∠B and an equal side i.e DF = AC.

To satisfy congruence, two sides and an angle have to be equal, therefore if AB = DE then the two triangles would be congruent

trasher [3.6K]3 years ago
7 0

Answer:

D). no, because the hypotenuses must have different lengths

Step-by-step explanation:

I just did the assignment on Edge and it's 100% correct.

Hope this helps!! Also heart and rate if you found this answer helpful!!  :)

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One less than one fourth the square of a number.
Free_Kalibri [48]

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1/4m²-1

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How do you work out? (step by step please)<br> 2x-4≥6(x-1)
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Recall that two angles are complementary if the sum of their measures is 90 degrees°. Find the measures of two complementary an
raketka [301]

Answer:

18° and 72°

Step-by-step explanation:

let x be the measure of one angle then the other is 3x + 18

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x + 3x + 18 = 90

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8 0
4 years ago
Please hurry. Solve the equation
Lelu [443]

The value of x is 5\sqrt[3]{25}.

Solution:

Given expression is -7=8-3 \sqrt[5]{x^{3}}.

Switch both sides.

8-3 \sqrt[5]{x^{3}}=-7

Subtract 8 from both side of the equation.

8-3 \sqrt[5]{x^{3}}-8=-7-8

-3 \sqrt[5]{x^{3}}=-15

Divide by –3 on both side of the equation.

$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}

\sqrt[5]{x^{3}}=-5

To cancel the cube root, raise the power 5 on both sides.

(\sqrt[5]{x^{3}})^5=(-5)^5

x^3=3125

To find the value of x, take square root on both sides.

\sqrt[3]{x^3}=\sqrt[3]{25}

x=5\sqrt[3]{25}

Hence the value of x is 5\sqrt[3]{25}.

5 0
3 years ago
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