Answer:
x = -3
Step-by-step explanation:
The line parallel to x=8 is another vertical line:
x = constant
To make it go through a point with an x-coordinate of -3, the constant must be -3.
Your line is ...
x = -3
Your answer is 21 for this one.
Tan ( a + b ) = [ tan a + tan b ] / [ 1 - (tan a)*(tan b) ];
let be a = 2x and b = x;
=> tan 3x = [ tan 2x + tan x ] / [ 1 - (tan 2x)*(tan x) ] => (tan 3x)*[ 1 - (tan 2x)*(tan x) ] =
tan 2x + tan x => tan3x - tan 3xtan 2xtanx = tan 2x + tan x => <span> tan 3x−tan 2x−tanx = tan 3xtan 2xtanx.</span><span />
Answer:

Step-by-step explanation:

I am joyous to assist you anytime.
1: Assuming this line is linear, the first thing to do is find the slope.
The slope formula is

, so in this case, it is

, which comes to

. Then, use your slope and one of the points given to write the point-slope formula of the linear equation, and then written in standard form:
y=

x-

.
2. Use the same process as in question 1 to find:
y=-7x+11