(5,465)(7,625)
slope(m) = (625 - 465) / (7 - 5) = 160/2 = 80
y = mx + b
slope(m) = 80
use either of ur points (5,465)...x = 5 and y = 465
now we sub and find b, the y int
465 = 80(5) + b
465 = 400 + b
465 - 400 = b
65 = b
equation is : y = 80x + 65...but we need it in standard form
y = 80x + 65
-80x + y = 65...multiply by -1 to make x positive
80x - y = -65 <== standard form
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function notation.....f(x) is the same as y
so y = 80x + 65 in function notation becomes f(x) = 80x + 65
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x axis will be days rented
y axis will be total cost
to graph :
y = 80x + 65.....the slope here is 80...the y int is (0,65)
to find the x int, sub in 0 for y and solve for x
0 = 80x + 65
-80x = 65
x = - 65/80 = - 13/16....so ur x int is (-13/16,0)
and if u need to find more points on ur line....
80x - y = -65....sub in any number for x, and solve for y
Solution is in attachment !
The function involves the initial speed of the object, and the height
from which it was launched, and whether it was launched upward
or downward. As you can see, your post was corrupted and is
unreadable. But when the object hits the ground, its height is zero.
Set the function equal to zero, solve the quadratic equation that you
have, discard the negative solution, and the positive solution is your
answer.
Answer: 40.68 %
Step-by-step explanation:
We need to find the interval between the values 0.2 and 2.2
0.2 ≤ z ≤ 2.2
Since in the standardized normal curve the mean 5.8 will be 0
Area for z values ≥ 0.2 ⇒ 0.0793 and area for z ≤ 2.2
area between 0 and 0.2 is 0.0793 ; and area between 0 to 2.2 is 0.4861
this last value includes the previous value at the left of z = 0.2
As we are looking for participants in the interval 0.2 ≤ z ≤ 2.2 we need to subtract areas 0.4861 - 0.0793 = 0.4068 express in % is 40.68 %