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4 years ago

5

i am a number between 20 and 30. put me into 6 equal groups.ther is a even number in each group and one is left over. what numbe

r am i?

1 answer:

mihalych1998 [28]4 years ago

3 0

Answer:

25.

Step-by-step explanation:

Looks like you are 25 because the grouping is

4 4 4 4 4 4 1

Six sets of 4 and 1 is left over:- 6 * 4 = 24 and plus 1 gives 25.

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4/3 x −4 = 5 + x Help me please!

Soloha48 [4]

Answer:

The answer is D.

Step-by-step explanation:

4/3 x - 4 = 5 + x

4/3 x = 9 +x

1/3 x = 9

x = 27

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3 years ago

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4 years ago

Cedric's basketball team scored fewer than 78 points in their last game. Which of the following inequalities represents the numb

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3 years ago

Which expression is equivalent to -1/23 (x+24)

mr_godi [17]

Answer:

-1/23x+-1.043478261

Step-by-step explanation:

Distribute -1/23 to x and 24

-1/23 times x equals -1/23x

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3 years ago

Find the values of b such that the function has the given maximum value.

gizmo_the_mogwai [7]

So, the equation has a leading term with a negative coefficient, and is a quadratic, meaning is a parabola opening downwards, so it goes up and up and up and then makes a U-turn then down down, so it has a maximum point, that is, at the vertex point

so.. where the dickens is the vertex at?
we're asked to make the vertex with a y-coordinate of 104, so the maximum value is 104

well
$\bf y = {{ a}}x^2{{ +b}}x{{ +c}}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)\\\\
-----------------------------\\\\
\textit{so we want }\implies {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}=104
\\\\
\textit{let's take a peek at your equation}\quad 
\begin{array}{ccccllll}
f(x)=&-x^2&+bx&-17\\
f(x)=&-1x^2&+bx&-17\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\\\\
thus
\\\\
(-17)=\cfrac{b^2}{4(-1)}=104$

solve for "b"

5 0

4 years ago