Help me PLEASE asap !! ill mark u as brainliest but you have to be CORRECT
1 answer:
You might be interested in
Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as
n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) = =
=
=
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
Answer:
(0, -1)
Step-by-step explanation:
There are multiple ways of solving this however- since both equations are already in Y-Intercept form, we will use the "Equal Values Method"
First, since both equations are equal to Y, we can set them equal to each other and solve for X
To start, you must eliminate the fraction using a "fraction buster" multiply EVERYTHING by 4 then simplify.
Since we still have a fraction, we shall do it one more time. This time we multiply by 3
Now, solve how you normally would.
9x = 6x
-6x
3x = 0
X = 0
Now, since we know what X would equal in the solution, we are able to plug in X as 0 in one of our equations. We can choose the first one!
Now solve which would lead to y = -1
You have your solution as
(X,Y)
(0,-1)
Hope this helps!