Answer:
Answer of the "different" question is 20
Answer of the "same" three questions: 12.
Step-by-step explanation:
The interquartile range is found by
Order the data from least to greatest: 45, 47, 48, 50, 53, 56, 59, 60, 62, 65
Find the median the median in this case is 53+56 / 2 = 54.5
Calculate the median of both the lower and upper half of the data: the median of the lower half 45, 47, 48, 50, 53 is 48 (first quartile) while the median of the upper half 56, 59, 60, 62, 65 (third quartile) is 60.
Thus, the interquartile range is the difference between the upper and lower medians: 60 - 48 = 12.
The range of the middle half of the data is also the interquartile range which is 12.
The range of the data set is the largest data minus the least: 65 - 45 = 20.
The different question among all these is the range of the data set which is 20.
Answer of the same three: What is the interquartile range of the data?
What is the range of the middle half of the data?
What is the difference between the range of the third quartile and the range of the first quartile?
Answer is 12
denotes the sum of the first 
terms of a geometric series with first term 
and common ratio 
, then
, 
, and 
. So the value of the sum is