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4 years ago

What is an rational number and irrational number between 7.7 and 7.9

Mathematics

1 answer:

avanturin [10]4 years ago

4 0

Rational number is 7.8 irrational numbers is 7.7 and 7.9

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Q.3 Write the factors of 28 in circle A and the factors of 32 in circle B. Write

marissa [1.9K]

Answer: The largest common factor of 28 and 32 is 4.

Step-by-step explanation:

The factors of 28 are 1, 2, 4, 7, 14, 28

The factors of 32 are 1, 2, 4, 8, 16, 32

5 0

2 years ago

Which graph represents the function f(x)=√x-2+3?

LUCKY_DIMON [66]

I believe is the second one on first picture(starts with (-2,1) and ends with (7,4)

4 0

3 years ago

The use of social networks has grown dramatically all over the world. In a recent sample of 24 American social network users and

Nady [450]

Answer:

The 99% confidence interval for the true mean amount of time Americans spend social networking each day is (3.02 hours, 3.36 hours).

Step-by-step explanation:

The (1 - α)% confidence interval for population mean when the population standard deviation is not known is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}$

The information provided is:

$n=24\\\bar x=3.19\ \text{hours}\\s=0.2903\ \text{hours}$

Confidence level = 99%.

Compute the critical value of t for 99% confidence interval and (n - 1) degrees of freedom as follows:

$t_{\alpha/2, (n-1)}=t_{0.01/2, (24-1)}=t_{0.005, 23}=2.807$

*Use a t-table.

Compute the 99% confidence interval for the true mean amount of time Americans spend social networking each day as follows:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}$

$=3.19\pm 2.807\times \frac{0.2903}{\sqrt{24}}\\\\=3.19\pm 0.1663\\\\=(3.0237, 3.3563)\\\\\approx (3.02, 3.36)$

Thus, the 99% confidence interval for the true mean amount of time Americans spend social networking each day is (3.02 hours, 3.36 hours).

6 0

3 years ago

The following data show the number of hours per day 12 adults spent in front of screens watching television-related content. 1.

Oksanka [162]

Answer:

99% Confidence interval: (2.9,6.7)

Step-by-step explanation:

We are given the following data set:

1.8, 4.7, 4.1, 5.2, 7.6, 7.3, 5.7, 3.2, 5.4, 1.9, 2.7, 8.1

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$\bar{x} =\displaystyle\frac{57.7}{12} = 4.8$

Sum of squares of differences = 51.18

$s = \sqrt{\dfrac{51.18}{11}} = 2.16$

99% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 11 and}~\alpha_{0.01} = \pm 3.106$

$4.8 \pm 3.106(\dfrac{2.16}{\sqrt{12}} )\\\\ = 4.8 \pm 1.937 \\\\= (2.863,6.737)\approx (2.9,6.7)$

(2.9,6.7) is the required 99% confidence interval for average number of hours per day adults spend in front of screens watching television-related content.

4 0

3 years ago

Find the missing factor A that makes the equality true 8x 3 =(−2x)(A)

Snezhnost [94]

A = -12

hope this helps, have a great day
mark brainliest:)!!

8 0

3 years ago

Read 2 more answers