4 years ago

What is an rational number and irrational number between 7.7 and 7.9

1 answer:

4 0

Rational number is 7.8 irrational numbers is 7.7 and 7.9

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Nonamiya [84]

generate the first few terms using the recursive formula

$a_{2}$ = - 7 × $\frac{1}{3}$ = - $\frac{7}{3}$

$a_{3}$ = - $\frac{7}{3}$ × $\frac{1}{3}$ = - $\frac{7}{9}$

$a_{4}$ = - $\frac{7}{9}$ × $\frac{1}{3}$ = - $\frac{7}{27}$

r = $a_{2}$ / $a_{1}$ = $\frac{1}{3}$

the n th term formula (explicit ) for a geometric sequence is

$a_{n}$ = $a_{1}$ $r^{n-1}$ = - 7( $\frac{1}{3}$ )^(n - 1)

6 0

3 years ago

lana [24]

A^2-3a+14 is the answer :)

8 0

3 years ago

Inga [223]

I think the answer is true.

6 0

4 years ago

beks73 [17]

$f(x)=-3x\qquad g(x)=5x-6\\\\g(f(x))=5(-3x)-6=\boxed{-15x-6}$

$f(x)=x-6\qquad g(x)=x^2+6x-2\\\\g(f(x))=(x-6)^2+6(x-6)-2=x^2-12x+36+6x-36-2=\\\\=\boxed{x^2-6x-2}$

$f(x)=4x+3\qquad g(x)=2x^2-x+1\\\\g(f(x))=2(4x+3)^2-(4x+3)+1=2(16x^2+24x+9)-4x-3+1=\\\\=32x^2+48x+18-4x-3+1=\boxed{32x^2+44x+16}$

$f(x)=2x^2\qquad g(x)=8x^2+3x\\\\g(f(x))=8(2x^2)^2+3(2x^2)=8\cdot4x^4+6x^2=\boxed{32x^4+6x^2}$

7 0

3 years ago

Evgesh-ka [11]

The answer is a (19.25)

8 0

3 years ago