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BlackZzzverrR [31]
3 years ago
11

the volume of a rectangular prism is 72 cubic centimeters the prism is 2 centimeters wide and 4 centimeters high what is the len

gth of the prism
Mathematics
2 answers:
Evgesh-ka [11]3 years ago
7 0
You do 2 x 4 = 8
then you just need to divide 72 by 8
to give you the length
72/8 = 9

hope this helps you<span />
spin [16.1K]3 years ago
5 0
The length of the prism is 9 cm
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3 years ago
Heights​ (cm) and weights​ (kg) are measured for 100 randomly selected adult​ males, and range from heights of 139 to 192 cm and
Bumek [7]

Answer:

The weight of an adult male who is 158 cm tall is 59.32 kg.

Step-by-step explanation:

The regression equation representing the relationship between height and weight of a person is:

\hat y=-105+1.04 x

Here,

<em>y</em> = weight of a person (in kg)

<em>x</em> = height of a person (in cm)

The information provided is:

\bar x=167.77\ \text{cm}\\\bar y=81.54\ \text{cm}\\r(X, Y)=0.201\\p-value=0.045

The significance level of the test is, <em>α</em> = 0.01.

The hypothesis to test the significance of the correlation between height and weight is:

<em>H₀</em>: There is no relationship between the height and weight, i.e. <em>ρ</em> = 0.

<em>Hₐ</em>: There is a relationship between the height and weight, i.e. <em>ρ</em> ≠ 0.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level, then the null hypothesis will be rejected and vice-versa.

According to information provided:

<em>p</em>-value = 0.045 > 0.01

The null hypothesis will not be rejected at 1% level of significance.

Thus, concluding that there is no relationship between the height and weight.

Compute the weight of an adult male with height, <em>x</em> = 158 cm as follows:

\hat y=-105+1.04 x

  =-105+(1.04\times 158)\\=-105+164.32\\=59.32

Thus, the weight of an adult male who is 158 cm tall is 59.32 kg.

6 0
3 years ago
If an object takes 7 second to fall to the ground, what was its initial height? Show your work.
Verdich [7]

Answer:240.1 m

Step-by-step explanation:

We are given the following equation that models the the time it takes to an object to fall to the ground:

t_{(H)}=\sqrt{\frac{2H}{g}}

Where:

t_{(H)}=7 s is the time it takes to the object to fall to the ground

H is the object's initial height

g=9.8 m/s^{2} is the acceleration due gravity

Isolating H:

t^{2}=(\sqrt{\frac{2H}{g}})^{2}

t^{2}=\frac{2H}{g}}

H=\frac{t^{2}g}{2}

Solving with the given data:

H=\frac{(7 s)^{2}(9.8 m/s^{2})}{2}

H=240.1 m This is the initial height

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Skew lines are not parallel and do not intersect.

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