Answer:
-2, -6, & -18
Step-by-step explanation:
The answer is x².
f(x) = <span>5x - 6
</span>g(x) = x²<span> - 5x + 6
(f + g)(x) = f(x) + g(x)
= </span>5x - 6 + x² - 5x + 6
= x² + 5x - 5x + 6 - 6
= x² + 0 + 0
= x²
Answer:
<h2>{1,2,3,4,5,6,7}</h2>
Step-by-step explanation:
The roster method consists by listing all elements inside brackets.
In this case, it's not provided any specific characteristics, so, basically, we describe elements by its position.
<u>Simplifying the equation:</u>
We are given the bi-quadratic equation:
9x⁴-3x²+1
to factorise this equation, we will convert it to a quadratic equation and factor it from there
in the given equation, let x² = y
now, the equation looks like:
9y² - 3y + 1
<u>Finding the Factors </u><em><u>(in terms of y)</u></em><u>:</u>
Using the quadratic formula: x = -b±√(b²-4ac) / 2a
replacing the variables in the equation
y = [-(-3) ± √[(-3)² - 4(9)(1)]]/2(9)
y= [3 ± √-27]/18
y = (1 ± √-3 / 6)
The 2 solutions are:
y = (1 + √-3 / 6) and y = (1 - √-3 / 6)
<u>Finding the values of 'x':</u>
<em>Since y = x²:</em>
x² = (1 + √-3 / 6) and x² = (1 - √-3 / 6)
<em>taking the square root of both sides</em>
x = √(1 + √-3 / 6) and x = √(1 - √-3 / 6)
As we can see, the given equation has complex roots and cannot be simplified further
the image and the pre-image are the same thing, which means that T and S are inverse operations.
<h3>How does the pre-image relate to the final image?</h3>
Here we have two transformations:
T(x, y) = (x + 3, y - 1)
S(x,y) = (x - 3, y + 1).
Now, let's start with a point (x, y), we will apply T first:
T(x, y) = (x + 3, y - 1)
Now our point is (x + 3, y - 1), and at that point, we apply the transformation S.
S(x + 3, y - 1) = (x + 3 - 3, y -1 + 1) = (x, y)
So the image and the preimage are the same thing, which means that T and S are inverse operations.
If you want to learn more about transformations:
brainly.com/question/4289712
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