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lukranit [14]
3 years ago
7

How much interest is earned on a principal of $9.02 invested at an interest

Mathematics
1 answer:
kow [346]3 years ago
3 0
To find the simple interest, we multiply 9.02 × 0.08 × 3 to get that: $2.16- answer
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Jeff needs to buy food and medication for six cats and one dog. The cost of food and medication for a cat is $5 less than two-th
Elodia [21]
Let x be the amount that Jeff spent for the food and medication of his dog. With this representation, the cost of food and medication for each cat is 2x/3 - 5. The equation that best represent the given situation is


                            x + 6(2x/3 - 5) = 195

The value of x from the equation is 45. Jeff spent $45
8 0
2 years ago
Find the sum of the three expressions and choose the correct answer.
worty [1.4K]
(-2u^3v + 5uv - 1) +(7u^3v - 2u^2v^2) +(5u^2v^2 - uv + 6)=\\\\ -2u^3v + 5uv - 1 +7u^3v - 2u^2v^2 +5u^2v^2 - uv + 6= \\ \\ (7u^3v-2u^3v)+(5u^2v^2-2u^2v^2)+(5uv-uv)+(6-1)=\\\\ \boxed{5u^3v+3u^2v^2+4uv+5}
5 0
3 years ago
Read 2 more answers
Please answer me this question ​
Jobisdone [24]

Answer:

x = 2

y = 3

Step-by-step explanation:

\left \{ {{0.4x + 0.3y = 1.7} \atop {0.7x - 0.2y = 0.8}} \right.

\left \{ {{2(0.4x + 0.3y) = 2 * 1.7} \atop {3(0.7x - 0.2y) = 3 * 0.8}} \right.

\left \{ {{0.8x + 0.6y = 3.4} \atop {2.1x - 0.6y) = 2.4}} \right.

2.9x = 5.8

29x = 58

x = 2

0.3y + 0.4x = 1.7

0.3y + 0.4 * 2 = 1.7

0.3y + 0.8 = 1.7

0.3y = 0.9

3y = 9

y = 3

4 0
2 years ago
HELPPPPP ASP PLZZZZZ
-Dominant- [34]

Answer:

(f-g)(x)

f(x)-g(x)

x^{2} -6x-27-x+9

x^{2} -7x-18

----------------------

(f*g)(x)

=f(x)g(x)

(x^{2} -6x-27)(x-9)

=x^{3} -15x^{2}+27x+243

----------------------

\frac{f}{g} (x)

\frac{x^{2} -6x-27}{x-9}

\frac{(x-9)(x+3)}{x-9}

x+3

-----------------------

(f+g)(x)

f(x)+g(x)

=x^{2} -6x-27+x-9

=x^{2} -5x-36

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<u>OAmalOHopeO</u>

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5 0
3 years ago
Well, I have to write 20 words, so... I think this is enough.
Varvara68 [4.7K]
<h3>Answer: Choice D</h3><h3>m = n</h3><h3>b = sqrt(pi)*a</h3>

=====================================================

Explanation:

Each circle has a radius of 'a'. So r = a.

The area of each circle is pi*r^2 = pi*a^2

The area of each square with side length b is b^2

The two stacks have the same volume only when the circle area is equal to the square area, so whenever pi*a^2 = b^2 is true.

Solving for b leads to b = sqrt(pi*a^2) = sqrt(pi)*a

The stacks must also be the same height for the volumes to be the same, so m = n as well.

6 0
3 years ago
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