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Nady [450]
3 years ago
5

You are buying a used car which costs $12,000. You plan to sell the car after keeping it for 5 years. Research shows that this c

ar will lose value at a rate of 8% per year. How much will tbe car be worth after 5 years?
Mathematics
2 answers:
slamgirl [31]3 years ago
4 0

Answer:

your car would be worth 500 dollars

Step-by-step explanation:

Anarel [89]3 years ago
4 0

\text{Use the formula:}\,A=P(1-r)^t\\\\\text{Plug your values into the equation}\\\\A=12,000(1-0.08)^5\\\\\text{Solve:}\\\\12,000(1-0.08)^5\\\\12,000(0.92)^5\\\\12,000(0.659)\\\\\boxed{\$7,908.98}

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olga2289 [7]
9 tens because 10 time 9 is 90 and 2 ones 
8 0
3 years ago
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Keith ran in a marathon. it took him 3 hours and 2 minutes to run 26 miles. if he ran at the same rate for the whole race, how m
stiks02 [169]
First, you have to find how many minutes he ran which would be 182 minutes. Then, to find out how many minutes he spent running each mile, you divide by 26. 182/26=7. 7 minutes per mile.
7 0
4 years ago
What is the perimeter and area of the shape given?
anygoal [31]

The perimeter of the given shape is 63.50 units and its area is 170.625 square units.

Step-by-step explanation:

Step 1:

First, we need to determine the distance between each of the points in the shape ABCDEFGH.

There are vertical lines and horizontal lines. The distances between vertical lines are found by calculating the difference in y values while for horizontal lines, the distances are found by calculating the difference between the x values.

Step 2:

Distance of line AB, 15 - 4.5 = 10.5,

Distance of line BC, 14 - 8 = 6,

Distance of line CD, 15 - 10 = 5,

Distance of line DE, 8 - 3 = 5,

Distance of line EF, 15 - 10 = 5,

Distance of line FG, 3 - (-2.25) = 5.25,

Distance of line GH, 15 - 4.5 = 10.5 and

Distance of line AH, 14 - (-2.25) = 16.25.

Step 3;

The area of ABCDEFGH = The area of ABGH - the area of CDEF.

The area of ABGH = Length × Width = AH × AB = 16.25 × 10.5 = 170.625 square units.

The area of CDEF = Length × Width = CD × DE = 5 × 5 = 25 square units.

The area of ABCDEFGH = 170.625 - 25 = 145.625 square units.

Step 4:

The perimeter of shape ABCDEFGH is just the sum of all its lines.

Perimeter of ABCDEFGH = 10.5 + 6 + 5 + 5 + 5 + 5.25 + 10.5 + 16.25 = 63.50 units.

7 0
4 years ago
Graph the rational function y=x/x^2+2x+1. Both branches of the rational function pass through which quadrant?
Hitman42 [59]

Answer:

Quadrant 3

Step-by-step explanation:

Here we have to graph the function y = x/(x^2 + 2x + 1)

The denominator can be factored.

x^2 + 2x + 1 = (x + 1)(x + 1)

y = x/(x + 1)(x + 1)

Now we have to graph this function and see in which quadrant the function's both branches passes through.

Herewith I have attached the graph.

Here we can see both branches pass through Quadrant 3.

I hope this will helpful.

Thank you.


4 0
3 years ago
Read 2 more answers
I don’t know how to solve this
Lady_Fox [76]

Answer:

\theta =2\pi k,\ \ k\in Z\ \\\text{or}\ \\\theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z

Step-by-step explanation:

Given:

\cos \theta-\sqrt{3}\sin \theta=1

Divide this equation by 2:

\dfrac{1}{2}\cos \theta-\dfrac{\sqrt{3}}{2}\sin \theta=\dfrac{1}{2}

Note that

\cos \dfrac{\pi }{3}=\dfrac{1}{2}\\ \\\sin \dfrac{\pi }{3}=\dfrac{\sqrt{3}}{2}

So, the previous equation is

\cos \dfrac{\pi}{3}\cdot \cos \theta-\sin \dfrac{\pi}{3}\cdot \sin \theta=\dfrac{1}{2}

Remind that

\cos x\cos y-\sin x\sin y=\cos (x+y),

then

\cos \left(\dfrac{\pi}{3}+\theta\right)=\dfrac{1}{2}

The solution of this equation is

\dfrac{\pi}{3}+\theta=\pm \arccos \dfrac{1}{2}+2\pi k,\ \ k\in Z\\ \\\dfrac{\pi}{3}+\theta=\pm \dfrac{\pi}{3}+2\pi k,\ \ k\in Z\\ \\\theta =2\pi k,\ \ k\in Z\ \text{or}\ \theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z

8 0
3 years ago
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