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Ira Lisetskai [31]
3 years ago
6

Consider the following population data:________.

Mathematics
1 answer:
AysviL [449]3 years ago
7 0

Answer:

a. 30

b. 11.04

c. 144.16

d. 12.00

Step-by-step explanation:

40 44 17 14 26

Rearrange the data

14, 17, 26, 40, 44

a. Calculate the range.

Range

Range can calculated as:

Maximum value - Minimum value

= 44 - 14

= 30

b. Calculate MAD. (Round your intermediate calculations to 4 decimal places and final answer to 2 decimal places.)

MAD

The formula for MAD( Mean Absolute Deviation) = x - Mean/5

Step 1

We find the mean

Mean = Sum of terms/ Number of terms

14 + 17 + 26 + 40 + 44/5

= 141/5

= 28.2

Step 2

Mean Absolute Deviation of the Population =

|14 - 28.2| + |17 - 28.2| + |26 - 28.2| + |40 - 28.2| + |44 - 28.2|

= 14.2 + 11.2 + 2.2 + 11.8 + 15.8/5

= 11.04

c. Calculate the population variance. (Round your intermediate calculations to 4 decimal places and final answer to 2 decimal places.)

Population variance

The formula for Population variance

= (x - Mean)²/n

n = 5

Population variance = (14 - 28.2)² + (17 - 28.2)² + (26 - 28.2)² + (40 - 28.2)²+ (44 - 28.2)²/5

= 201.64 + 125.44 + 4.84 + 139.24 + 249.64/ 5

= 720.8/5

d. Calculate the population standard deviation. (Round your intermediate calculations to 4 decimal places and final answer to 2 decimal places.)

Population standard deviation

Population Standard deviation formula = √ Population Variance

= √144.16

= 12.00666482

Approximately to 2 decimal places

= 12.00

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Solve for x in the equation 9- x/4=2
jeka57 [31]

Answer:

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5 0
3 years ago
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William invested $5000 in an account that earns 3.5% interest, compounded
zvonat [6]

Answer:

Option B. $5737.62

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=4\ years\\ P=\$5,000\\ r=0.035\\n=1  

substitute

A=\$5,000(1+\frac{0.035}{1})^{1*4}  

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5 0
3 years ago
How many times greater is the value of 5 in 3,590 than the value of 5 in 359 ?
Tresset [83]

Answer:

10 times greater is the value of 5 in 3,590 than the value of 5 in 359.

Step-by-step explanation:

To find : How many times greater is the value of 5 in 3,590 than the value of 5 in 359 ?

Solution :

The place value stem is

Thousand     Hundred     Tens    Ones

  1000               100            10         1

The value of 5 in 3,590 is at hundred place

So, 5\times 100=500

The value of 5 in 359 is at tens place

So, 5\times 10=50

Number of time greater is the value of 5 in 3,590 than the value of 5 in 359 is given by,

n=\frac{500}{50}

n=10

Therefore, 10 times greater is the value of 5 in 3,590 than the value of 5 in 359.

4 0
3 years ago
The straight line ax+by=1passes through the points (1,4)and (3,1).Find the values of a and b?
Molodets [167]

Answer:

a= 3/11

b = 2/11

Step-by-step explanation:

a(1) + b(4) = 1

a + 4b = 1

a(3) + b(1) = 1

3a + b = 1

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a + 4(1-3a) = 1

a+ 4-12a = 1

-11a = -3

a = 3/11

b = 1-3(3/11)

b= 2/11

3 0
3 years ago
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