Which of the following is the most appropriate unit to describe the time you can drive a car based on the amount of gas?

Mathematics

1 answer:

sukhopar [10]3 years ago

6 0

The correct answer is "Minutes per gallon, because the independent quantity is the gallons"

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Find the mean of 3,2,2,5,1,3,2,0,5

LekaFEV [45]

Answer:

2.56

Step-by-step explanation:

(3+2+2+5+1+3+2+0+5)/9=2.55555555556...

8 0

2 years ago

Solve 9/10=z/8 . Round to the nearest tenth.

kompoz [17]

$\boxed {Question}$
$\frac{9}{10} = \frac{z}{8}$

$\boxed {Cross \ multiply}$
$10z = 8 \times 9$

$\boxed {Evaluate}$
$10z = 72$
$z = 72 \div 10$
$z = 7.2$

$\Longrightarrow \bf \ Answer \ : \ z = 7.2$

4 0

3 years ago

Show work and explain with formulas.

Juli2301 [7.4K]

20 Answer: a₁ = 4

Step-by-step explanation:

$a_n=324,\ r=3,\ n=5\\\\a_n=a_1 \cdot r^{n-1}\\\\324=a_1\cdot 3^{5-1}\\\\\dfrac{324}{3^4}=a_1\\\\\dfrac{324}{81}=a_1\\\\\large\boxed{4}=a_1$

21 Answer: n = 13

Step-by-step explanation:

$a_n=\dfrac{1}{64},\ a_1=64,\ r=\dfrac{1}{2}\\\\a_n=a_1 \cdot r^{n-1}\\\\\dfrac{1}{64}=64\cdot \bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{64\cdot 64}=\bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{2^6\cdot 2^6}=\dfrac{1}{2^{n-1}}\\\\6+6=n-1\\\\\large\boxed{13}=n$

22 Answer: n = 5

Step-by-step explanation:

$a_n=48,\ a_1=1875\ r=\dfrac{2}{5}\\\\a_n=a_1 \cdot r^{n-1}\\\\48=1875\cdot \bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{48}{1875}=\bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{16}{625}=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\\bigg(\dfrac{2}{5}\bigg)^4=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\4=n-1\\\\\large\boxed{5}=n$