



= Let Martina's cousin's age be = n
= Let her age be = n+12
After four years,
Cousin's age = n+4
Her age = n+12+4=n+16
But according to the question her age = 3(n+4) = 3n+12
Thus,
3n+12=n+16
3n-n=16-12
2n=4
n=4/2

Thus ,
Her cousin's present age = n = 2
Her cousin's present age = n = 2Her present age = n+12 = 2+12=14
Question:
Simplify the radical expressions

![10.\ \sqrt[3]{135}](https://tex.z-dn.net/?f=10.%5C%20%5Csqrt%5B3%5D%7B135%7D)
Answer:





![\sqrt[3]{24} = 2 \sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%7D%20%3D%202%20%5Csqrt%5B3%5D%7B3%7D)
![\sqrt[3]{81} =3\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B81%7D%20%3D3%5Csqrt%5B3%5D%7B3%7D)

![\sqrt[3]{40} = 2 \sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B40%7D%20%3D%202%20%5Csqrt%5B3%5D%7B5%7D)
![\sqrt[3]{135} =3\sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%20%3D3%5Csqrt%5B3%5D%7B5%7D)
Step-by-step explanation:
Express 63 as 9 * 7

Split:



Express 48 as 16 * 3

Split



Express 75 as 25 * 3

Split


Express 99 as 9 * 11

Split


Express 92 as 4 * 23



Express 24 as 8 * 3
![\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%7D%20%3D%20%5Csqrt%5B3%5D%7B8%7D%20%2A%20%5Csqrt%5B3%5D%7B3%7D)
Express 8 as 2^3
![\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%7D%20%3D%20%5Csqrt%5B3%5D%7B2%5E3%7D%20%2A%20%5Csqrt%5B3%5D%7B3%7D)
![\sqrt[3]{24} = 2 \sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24%7D%20%3D%202%20%5Csqrt%5B3%5D%7B3%7D)
![7.\ \sqrt[3]{81}](https://tex.z-dn.net/?f=7.%5C%20%5Csqrt%5B3%5D%7B81%7D)
Express 81 as 27 * 3
![\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B81%7D%20%3D%5Csqrt%5B3%5D%7B27%7D%2A%5Csqrt%5B3%5D%7B3%7D)
Express 27 as 3^3
![\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B81%7D%20%3D%5Csqrt%5B3%5D%7B3%5E3%7D%2A%5Csqrt%5B3%5D%7B3%7D)
![\sqrt[3]{81} =3\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B81%7D%20%3D3%5Csqrt%5B3%5D%7B3%7D)
Express 128 as 64 * 2


![9.\sqrt[3]{40}](https://tex.z-dn.net/?f=9.%5Csqrt%5B3%5D%7B40%7D)
Express 40 as 8 * 5
![\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B40%7D%20%3D%20%5Csqrt%5B3%5D%7B8%7D%20%2A%20%5Csqrt%5B3%5D%7B5%7D)
![\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B40%7D%20%3D%20%5Csqrt%5B3%5D%7B2%5E3%7D%20%2A%20%5Csqrt%5B3%5D%7B5%7D)
![\sqrt[3]{40} = 2 \sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B40%7D%20%3D%202%20%5Csqrt%5B3%5D%7B5%7D)
![10.\ \sqrt[3]{135}](https://tex.z-dn.net/?f=10.%5C%20%5Csqrt%5B3%5D%7B135%7D)
Express 135 as 27 * 5
![\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%20%3D%5Csqrt%5B3%5D%7B27%7D%2A%5Csqrt%5B3%5D%7B5%7D)
Express 27 as 3^3
![\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%20%3D%5Csqrt%5B3%5D%7B27%7D%2A%5Csqrt%5B3%5D%7B5%7D)
![\sqrt[3]{135} =3\sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%20%3D3%5Csqrt%5B3%5D%7B5%7D)
The answer would be 942.
since the formula for volume of a cylinder is the area of the base times the height you would need to multiply pi times 10^2 and then times the height of 3.
3.14 * 10^2 = 314
314 * 3 = 942
I hope this helped :)
There are 12 wheels on 4 tricycles.