Answer:
Q16a: 432 cm³
Q16b: sides: 20 m, 6 m; height: 13 m.
Step-by-step explanation:
<h3>Q16a</h3>
Each cube will have a volume ...
V = s³
V = (6 cm)³ = 216 cm³
The two cubes together will have a volume that is twice that.
The cuboid volume is 432 cm³.
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<h3>Q16b</h3>
Let h represent the height of the trapezium. Then its area is ...
A = 1/2(b1 +b2)h
169 = 1/2((h +7) +(h -7))h = 1/2(2h²) = h²
h = √169 = 13 . . . . . distance between the parallel sides
The side lengths are h+7 = 20 m and h-7 = 6 m. The distance between them is 13 m.
Answer:5 and 3
Step-by-step explanation:
you can multiply 5x3 to get 15
Answer: (-4,9)
Step-by-step explanation:
Take the points and plot them on graph paper, revealing the midpoint
Answer:
0.3137 ; 0.2228
Step-by-step explanation:
Given a normal distribution :
Morning class :
Mean(Mm) = 71%
Standard deviation (Sm) = 12%
Afternoon class:
Mean(Ma) = 78%
Standard deviation (Sa) = 8%
M = Mm - Ma = (71 - 78) = - m7
S = √Sm + Sa = √12² + 8² = √208
A. What is the probability that a randomly selected student in the morning class has a higher final exam mark than a randomly selected student from an afternoon class?
P(morning > afternoon) = p(morning - afternoon > 0)
Using:
Z = (0 - (-7)) / S
Z = 7 / √208
Z = 0.4853628
P(Z > 0.49) = 0.3137
B)
What is the probability that the mean mark of four randomly selected students from a morning class is greater than the average mark of four randomly selected students from an afternoon class?
Using:
Z = (4 - (-7)) / S
Z = 11 / √208
Z = 0.7627127
P(Z > 0.49) = 0.2228
