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Keith_Richards [23]

3 years ago

8

The subject of the formula below is y. y=x-5 rearrange the formula to make x the subject

1 answer:

lana [24]3 years ago

4 0

Answer:

Step-by-step explanation:

y=x-5 add 5 to both sides

y+5 = x-5+5

x= y+5

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Martina is currently 12 years older than her cousin Joey. In 4 years she will be 3 times as old

Katarina [22]

$\Huge{\underline{\underline{\sf{\red{AnSwEr:}}}}}$

$\boxed{\sf{Martina's \: Present \: age = 14 \: years}}$

$\boxed{\sf{Her \: cousin's \: Present \: age = 2\: years}}$

$\Huge{\underline{\underline{\sf{\green{ExpLaNaTion:}}}}}$

= Let Martina's cousin's age be = n

= Let her age be = n+12

After four years,

Cousin's age = n+4

Her age = n+12+4=n+16

But according to the question her age = 3(n+4) = 3n+12

Thus,

3n+12=n+16

3n-n=16-12

2n=4

n=4/2

$\boxed{ \sf {n = 2}}$

Thus ,

Her cousin's present age = n = 2

Her cousin's present age = n = 2Her present age = n+12 = 2+12=14

5 0

3 years ago

Learning Task 1 4/625 11. 796 A. Simplify the radical expressions 1. V63 6. V24 2. 48 7. 781 3. 775 8. V128 4. 99 9. 340 5. 92 1

kompoz [17]

Question:

Simplify the radical expressions

$1.\ \sqrt{63$ $2.\ \sqrt{48$ $3.\ \sqrt{75$ $4.\ \sqrt{99$ $5.\ \sqrt{92$

$6.\ \sqrt[3]{24}$ $7.\ \sqrt[3]{81}$ $8.\ \sqrt{128}$ $9.\sqrt[3]{40}$ $10.\ \sqrt[3]{135}$

Answer:

$\sqrt{63}= 3 \sqrt7$

$\sqrt{48} = 4\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$\sqrt{99} = 3 \sqrt{11$

$\sqrt{92} = 2\sqrt{23$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$\sqrt{128} = 8 \sqrt{2}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

Step-by-step explanation:

$1.\ \sqrt{63$

Express 63 as 9 * 7

$\sqrt{63}= \sqrt{9 * 7$

Split:

$\sqrt{63}= \sqrt{9} * \sqrt7$

$\sqrt{63}= 3 * \sqrt7$

$\sqrt{63}= 3 \sqrt7$

$2.\ \sqrt{48$

Express 48 as 16 * 3

$\sqrt{48} = \sqrt{16*3}$

Split

$\sqrt{48} = \sqrt{16}*\sqrt{3}$

$\sqrt{48} = 4*\sqrt{3}$

$\sqrt{48} = 4\sqrt{3}$

$3.\ \sqrt{75$

Express 75 as 25 * 3

$\sqrt{75} = \sqrt{25*3}$

Split

$\sqrt{75} = \sqrt{25}*\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$4.\ \sqrt{99$

Express 99 as 9 * 11

$\sqrt{99} = \sqrt{9} * \sqrt{11}$

Split

$\sqrt{99} = 3 \sqrt{11$

$5.\ \sqrt{92$

Express 92 as 4 * 23

$\sqrt{92} = \sqrt{4} * \sqrt{23$

$\sqrt{92} = 2* \sqrt{23$

$\sqrt{92} = 2\sqrt{23$

$6.\ \sqrt[3]{24}$

Express 24 as 8 * 3

$\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}$

Express 8 as 2^3

$\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$7.\ \sqrt[3]{81}$

Express 81 as 27 * 3

$\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}$

Express 27 as 3^3

$\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$8.\ \sqrt{128}$

Express 128 as 64 * 2

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

$9.\sqrt[3]{40}$

Express 40 as 8 * 5

$\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}$

$\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$10.\ \sqrt[3]{135}$

Express 135 as 27 * 5

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

Express 27 as 3^3

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

4 0

3 years ago

The height of a cylinder is 3 units. Its radius is 10 units. What is the volume of the cylinder, in cubic units? (Use π = 3.14)

serg [7]

The answer would be 942.
since the formula for volume of a cylinder is the area of the base times the height you would need to multiply pi times 10^2 and then times the height of 3.

3.14 * 10^2 = 314
314 * 3 = 942

I hope this helped :)

8 0

3 years ago

Read 2 more answers

Answer if you actually know the answer

adoni [48]

Answer:

I think its 3.14 if

wrong tell me

7 0

3 years ago

Read 2 more answers

A tricycle has 3 wheel. how many wheel are there on 4 tricycles

DIA [1.3K]

There are 12 wheels on 4 tricycles.

4 0

4 years ago

Read 2 more answers