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3 years ago

A club has 10 members.

2 answers:

6 0

That is the combination of 10 over 3, which is calculated as the quotient of factorials:
n!/k!(n-k)!
where n = 10 and k = 3:
= 10!/3!(10 - 3)!
= 10!/3!*7!
= (10*9*8)/(3*2*1)
= 720/6
= 120
therefore there a re 120 possible different groups

SIZIF [17.4K]3 years ago

5 0

Okay so you have 10 members. So you would go 10 divided by 3 that is equal to 9 with one left over.

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The length of the sides b and c and angle B.

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Using the trigonometric ratio,

$\begin{gathered} sinA=\frac{a}{c} \\ \sin15^{\circ}=\frac{3}{c} \\ c=\frac{3}{\sin15^{\circ}} \\ c=11.59 \\ c\approx11.6 \end{gathered}$

Using the trigonometric ratio,

$\begin{gathered} \tan A=\frac{a}{b} \\ \tan15^{\circ}=\frac{3}{b} \\ b=\frac{3}{\tan15^{\circ}} \\ b=11.19 \\ b\approx11.2 \end{gathered}$

Using the angle sum property,

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Final answer:

The values are,

$\begin{gathered} b=11.2 \\ c=11.6 \\ B=75^{\circ} \end{gathered}$

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elena55 [62]

Hey there!

This seems like a algebraic expression

SO,
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Good luck on your assignment and enjoy your day

~ $LoveYourselfFirst:)$

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