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777dan777 [17]
3 years ago
9

Jamie is the accountant of a logistics company. In the month of December, $5,000 of wages remained unpaid. The accounting period

of the company ends in the month of December. What will be the adjusting entry passed by Jamie?
Mathematics
2 answers:
OleMash [197]3 years ago
8 0

Answer:

The adjusting entry passed by Jamie will be $5000.

Step-by-step explanation:

The full $5000 is wages expense, that will be booked for December only. The payments are not done, so we will credit the account wages payable.

As the payments are made, the wages payable will be debited and if the payments are made through bank, they will be credited in future months.

Note : nature of accounts wages expense = Profit and loss account

nature of wages payable = part of balance sheet

Hence, the adjusting entry passed by Jamie will be $5000.

Ymorist [56]3 years ago
3 0
Wages expenses. 5000
To wages payable. 5000
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1) Anna and Jason have summer jobs stuffing envelopes for two different companies. Anna earns $20 for every 400 envelopes she fi
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Answer:

The answer is below

Step-by-step explanation:

A) i)

For Anna initially, she has $0 from making 0 envelopes. After making 400 envelopes she has $20. Let x represent the number of envelopes and y the earnings. Hence this can be represented by the points (0, 0) and (400, 20). Using the equation of a line:

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x:   200     400       600     800     1000

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ii)

For Jason initially, he has $0 from making 0 envelopes. For every 250 envelopes he has $10. Let x represent the number of envelopes and y the earnings. Hence this can be represented by the points (0, 0) and (250, 10). Using the equation of a line:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-0=\frac{10-0}{250-0}(x-0)\\\\y=\frac{1}{25} x

The table is:

x:   200     400       600     800     1000

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The graph is plotted using geogebra online graphing

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c) Anna has a savings of $100. Hence this can be represented by the points (0, 100) and (250, 10). Using the equation of a line:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-100=\frac{20-0}{400-100}(x-0)\\\\y=\frac{1}{15} x+100

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