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Licemer1 [7]
3 years ago
14

If ∠ECD = 45° and ∠BED = 110° is ΔABE ~ ΔCDE? If so, by what criterion? A) yes, by AA criterion B) yes, by SAS criterion C) yes,

by SSA criterion D) no, not possible to tell.
Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
6 0
D not possible to tell
dangina [55]3 years ago
3 0

Answer: A) yes, by AA criterion

Just had this on USA Test Prep dawg.... that's what it said

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A local pizza restaurant surveyed a random sample of 150 people that live in their town about their favorite type of pizza. Of t
svlad2 [7]

Answer:

B) Yes, because the proportion of the sample whose favorite pizza is pepperoni is about 27%.

Step-by-step explanation:

From data of survey we can estimate the proportion of the sample whose favorite pizza is pepperoni. That is 40 (say pepperoni is the favorite) from 150 (total of sample).

Proportion would be \frac{40}{150}=0.27 that is 27%.

Now we can calculate 27% of total of residents (2,800). We should multiply 27% by 2,800.

0.27*2,800=756 which is close to 750.

So we can conclude that yes, 750 is a reasonable estimate because the proportion of the sample whose favorite pizza is pepperoni is about 27%  

7 0
3 years ago
Read 2 more answers
Subtract 3 hours, 50 minutes from 5 hours, 20 minutes.
Sati [7]
1 hour 30 mins because you add up the minutes from both individually and then subtract.
7 0
3 years ago
The equation y= 5280x gives the number of feet, y, in x miles. What does the number 5,280 represents in this relationship?
LiRa [457]
The 5280 represents the original feet
3 0
3 years ago
A convenience sample is a type of probability sample. <br> a. True <br> b. False
NeX [460]
I think the answer is A.
7 0
3 years ago
The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Viefleur [7K]

Answer:

6.68% or 0.0668

Step-by-step explanation:

Mean sheet length (μ) = 30.05 inches

Standard deviation (σ) = 0.2 inches

In a normal distribution, for any length X, the z-score is determined by the following expression:

z=\frac{X-\mu}{\sigma}

For X = 29.75, the z-score is:

z=\frac{29.75-30.05}{0.2}\\z=-1.5

A z-score of -1.5 corresponds to the 6.68th percentile of a normal distribution.

Therefore, the probability that a sheet selected at random will be less than 29.75 inches long is 6.68%.

6 0
3 years ago
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