4 years ago

Finding the value of x

Mathematics

2 answers:

lawyer [7]4 years ago

4 0

Answer:

4ft

Step-by-step explanation:

A) This is a Pythagorean Triple.

B) 3^2 +x^2=5^2

9+x^2=25

x^2=16

x=4

alexira [117]4 years ago

3 0

Answer:

It is 4

Step-by-step explanation:

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Read 2 more answers

Prove that (n+5)^2-(n+3)^2 is a multiple of 4 for all positive integer values of n

hodyreva [135]

Answer:

Proved

Step-by-step explanation:

Given

$(n+5)^2-(n+3)^2$

Required

Show that $(n+5)^2-(n+3)^2$ is a multiple of 4

Expand each bracket

$(n+5)(n+5)-(n+3)(n+3)$

Open brackets

$n^2 + 5x + 5x + 25 - (n^2 + 3x + 3x + 9)$

$n^2 + 10x + 25 - (n^2 + 6x + 9)$

Open bracket

$n^2 + 10x + 25 - n^2 - 6x - 9$

Collect Like Terms

$- n^2 + n^2 - 6n + 10n + 25 - 9$

$- 6n + 10n + 25 - 9$

$4n + 25 - 9$

$4n + 16$

Factorize

$4(n + 4)$

Hence, the multiples of $(n+5)^2-(n+3)^2$ are $4$ and $(n + 4)$

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