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2 years ago

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Suppose X1, X2, . . . , Xn is a random sample from an exponential distribution with parameter ????. Assume that Xi’s are indepen

dence and the individual pdf is given by: ????(x, ????) = ????????. Find the Maximum likelihood estimator of this function

1 answer:

Xelga [282]2 years ago

5 0

Step-by-step explanation:

whaatttttttttttttttt

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Two bells ring every 10 and 25 minutes respectively. They start ringing together at 6 a.m. At what time will they next ring toge

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Answer:

6:50

Step-by-step explanation:

The bell that rings every 10 min will ring at 6:00, 6:10, 6:20,6:30, 6:40, 6:50

The bell that rings every 25 min will ring at 6:00, 6:25, and 6:50

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Step-by-step explanation:

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2 years ago

8.4 divided by 10 = ?

ASHA 777 [7]

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If you're looking for a percentage it'd be 84%

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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2 years ago

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Simplify (-3c^-3w^5)^3<br> A -9w^8<br> B. -27cw^8<br> C. w^15/27c^9<br> D.-27w^15/c^9

kenny6666 [7]

Answer:

$\large\boxed{D.\ \dfrac{-27w^{15}}{c^9}}$

Step-by-step explanation:

$(-3c^{-3}w^5)^3\qquad\text{use}\ (ab)^n=a^nb^n\\\\=(-3)^3(c^{-3})^3(w^5)^3\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=-27c^{-3\cdot3}w^{5\cdot3}=-27c^{-9}w^{15}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=-27\left(\dfrac{1}{c^9}\right)w^{15}=\dfrac{-27w^{15}}{c^9}$

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2 years ago